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Old 17th November 2009, 12:44 AM   #11
Enzo is offline Enzo  United States
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I suspect he won;t be dropping the entire 13.8v ACROSS the transistor.
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Old 17th November 2009, 10:04 AM   #12
kroto is offline kroto  Indonesia
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Default Pd

I think that will be:
15*1,414= 21V (assuming the V_ripple not high)

Pd = Vin-Vreg*Iout
Pd = 21 - 13,8 * 50 (max)
Pd = 360W.

but how to use MosFET (HEXFET)?
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Old 18th November 2009, 07:35 AM   #13
Enzo is offline Enzo  United States
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I was being academic. 690 watts or 360 watts, how do you intend to dissipate all that power from one little TO220 transistor?
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Old 18th November 2009, 07:59 AM   #14
kroto is offline kroto  Indonesia
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Default parallel

paralleling of course, HEXFET is more rugged than BJT isn't?
so Pd max of 35W/pcs I think that was suitable.
360/35 = 10,28 or 10 pcs.
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Old 18th November 2009, 02:56 PM   #15
star882 is offline star882  United States
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Make a buck converter and you'll only need to use 2-3.
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Old 18th November 2009, 03:11 PM   #16
wg_ski is offline wg_ski  United States
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Quote:
Originally Posted by kroto View Post
I think that will be:
15*1,414= 21V (assuming the V_ripple not high)

Pd = Vin-Vreg*Iout
Pd = 21 - 13,8 * 50 (max)
Pd = 360W.

but how to use MosFET (HEXFET)?
At those current levels, a 15-0-15 trafo will give you closer to 15V DC out. Unloaded it will be 21. Dissipation will be significantly less, but still it would be a problem. I'd be more worried about a linear regulator dropping out than anything else. Star's idea of the buck converter is probably the best way to go about regulating this.
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