|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
Join Date: Mar 2008
Location: McLean, VA
|
Hello,
My name is Orazio and, even though I have been a member for quite a while, this is my first post. I have an old Dayton boxer fan [110V, .16A and 13W]. I would like to half the fan speed by reducing the voltage to, let's say 50V and, according to my calculation, I need a 4.3 watt resistor. Any idea where to get just one 110V 4.3w resistor? Thank you very much in advance. Regards, Orazio |
|
|
|
|
#2 |
|
Did it Himself
diyAudio Member
|
You've not quite got it right, resistors are specified in ohms not volts.
Fan equivalent resistance R = V / I = 110/0.16=687.5 ohms Therefore if you put a 687.5 ohm resistor in series with the fan you will halve the voltage the fan sees. With approx 55 volts across the resistor it will dissipate P = V^2 / R = (55x55)/687.5=4.4 watts The closest practical component is 680 ohms, 6 watts. Depending on the fan though it may not necessarily turn at half speed, you may have to experiment to find a suitable resistor to give you the speed you require.
__________________
www.readresearch.co.uk my website for UK diy audio people - designs, PCBs, kits and more Last edited by richie00boy; 30th October 2009 at 12:12 AM. |
|
|
|
|
#3 |
|
diyAudio Member
Join Date: Mar 2008
Location: McLean, VA
|
Sorry, my mistake, I should have written 825 ohms and 4.3 watts per the following table:
Original fan voltage: 110V Original fan current: 0.16A V=IR (Ohm's Law), so 110 = 0.16R => R = 110 / 0.16 = 687.5 Fan resistance: 687.5 Ohms Target voltage: 50V V=IR (Ohm's Law), so 50 = 687.5I => I = 50 / 687.5 = 0.073 Target current: 0.073A Voltage drop across resistor: 110V - 50V = 60V V=IR (Ohm's Law), so 60 = 0.073R => R = 60 / 0.073 = 825 Target resistance: 825 Ohms Power dissipated by resistor: 60V * 0.073A = 4.364W Thanks a lot. Orazio |
|
|
|
|
#4 |
|
diyAudio Member
Join Date: Mar 2007
|
You cannot reduce the speed of an induction motor by decreasing the voltage.
__________________
"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
|
|
|
|
#5 |
|
diyAudio Member
Join Date: Mar 2008
Location: McLean, VA
|
I could use a dimmer but it is not very convenient and wanted to simplify things.
|
|
|
|
|
#6 |
|
diyAudio Member
Join Date: Jan 2008
Location: So.Cal.
|
|
|
|
|
|
#7 |
|
diyAudio Member
Join Date: Apr 2008
Location: Carlisle, England
|
I have used dropper resistors on PC fans too.
I use the running current of the fans to determine the resitor required. I use two 12 volts fans in series with a resistor dropped from 60 volts. It does need a 10 watt resistor tho.
__________________
http://www.murtonpikesystems.co.uk PCBCAD40 pcb design software. |
|
|
|
|
#8 |
|
diyAudio Member
Join Date: Mar 2007
|
Brushless DC fans are basically induction motors with built in inverters, but the frequency changes with voltage.
__________________
"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
|
|
|
|
#9 |
|
diyAudio Member
Join Date: Oct 2008
Location: Vancouver
|
If its a 110v ac induction motor with a speed thats 3600 rpm (or multiple) than its speed is based on the 60 hz (60x60=3600 rpm)of the line voltage, adding a resistor will probably increase the current the motor draws, keeping the speed approximately the same. A dimmer might work.
|
|
|
|
|
#10 |
|
diyAudio Member
Join Date: Mar 2008
Location: McLean, VA
|
Chaps,
I have two of these fans, NOS - 25 yr old, cast iron, USA made - Dayton square AC axial fans, air flow 75 CFM, voltage rating @ 50/60 Hz 115, 4 11/16" square, 1 1/2" depth. Current rating is 0.16 Amp, power rating is 13W, speed 1800 RPM. Regards, Orazio |
|
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
|
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| reducing voltage | rtill | Solid State | 28 | 16th January 2009 02:45 PM |
| Reducing LED intensity | qguy | Everything Else | 8 | 8th February 2008 01:04 AM |
| Reducing midrange | qguy | Multi-Way | 5 | 21st October 2006 07:15 AM |
| reducing output | Lostcause | Power Supplies | 4 | 7th September 2006 10:50 PM |
| reducing hum | mrjcfreak | Tubes / Valves | 5 | 19th July 2004 03:26 PM |
| New To Site? | Need Help? |
| Page generated in 0.10288 seconds (77.15% PHP - 22.85% MySQL) with 10 queries |