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#1 |
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diyAudio Member
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Hello all.
I currently run my bench off of two 12V 7Ah lead-acid batteries, but if I'm to use my latest amplifier designs, I might need help keeping them charged. I use the batteries because I don't have a transformer that will supply the required current. So I thought of this. The batteries are kept charged constantly, and the trafo is protected by the current limiters. Large transients will be pulled from the batteries, with a limited amount of help from the input transformer. How will this do? ![]() Thank you, - keantoken
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#2 |
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diyAudio Member
Join Date: Sep 2006
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I don't see how this could work. The MOS transistors will be reversed biased by the charger, and they will be equivalent to a 12ohm resistor in series with a diode. Is this your intention?
And if the reversal is just a mistake, it won't work either: such current sources only work with depletion devices, such as jFETs. |
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#3 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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a 317 can give you a 1A CCS.
Are the peaks relatively short term? This will determine the size of the heatsink on the 317s.
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regards Andrew T. |
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#4 | ||
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diyAudio Member
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Quote:
Quote:
I have an LM7915C and an LM1815C, but no 12V regulators. I could probably make a two-transistor CCS using 2N3055/2955, but the JFET current source is more efficient and concise (I will probably have to use the BJTs since I don't have any JFets). So I'm assuming that since no one has pointed something out, it is okay for me to have the batteries constantly connected to power, so they'll be forever charged when I need to use them? - keantoken
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#5 | |
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diyAudio Member
Join Date: Sep 2006
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Quote:
You have to make sure the open circuit voltage of your transformer + rectifier cannot rise above 14V, otherwise you risk damaging your batteries in the long term. |
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#6 |
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diyAudio Member
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What about the impedance of the batteries? My reason for preferring the CCS variation is so that the trafo will be allowed to improve the line regulation, without high series impedance. Is this reasonable or do the batteries already have a fairly low series resistance?
Thank you, - keantoken
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#7 |
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diyAudio Member
Join Date: Sep 2006
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Even a large transformer has a relatively large internal resistance compared to a battery.
And yours is on the smallish side. Anyway, by definition, any current generator inherently has a high internal resistance. |
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#8 | |
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diyAudio Member
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Quote:
Will it damage my batteries if the voltage goes above 14V while charging, or does this limit just apply to float charge? I think there is something wrong with my setup. At first while I was charging one battery, I found that the other battery was getting warm instead! Following all the wire, there was no logical way this could happen. Anyways, this resulted in the battery getting charged the wrong direction... I don't think it got completely discharged, but now the voltage across it goes to 15V when charging, and the lightbulb does not light up. Thanks for your help, - keantoken
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#9 |
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diyAudio Member
Join Date: Mar 2007
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Lead acid batteries must be voltage charged.
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"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
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#10 |
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diyAudio Member
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Does that mean you have to use a CCS?
I am charging a 12V, 7Ah sealed lead-acid battery. - keantoken
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| Thread | Thread Starter | Forum | Replies | Last Post |
| Would this work ? | LesPaulStandard | Instruments and Amps | 3 | 4th May 2006 02:14 AM |
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