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Old 15th June 2008, 04:37 PM   #1
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Default Regulator for Battery ??

I have 3 pieces of older test equipment that use 1.345v mercury batteries.
I believe they are either used as reference voltages, or one unit uses 2 batteries (for +1.345v) and might be used in a dc bridge (for a null detector unit).

I have found these two things...

1)....For cameras, there is a "silver oxide" 1.55v battery and a zinc disc or other adapter, to mimic the mercury's steady 1.345v.
(or there's a "Wein Cell", zinc-air battery, but only lasts a few months)
http://www.cameracheckpoint.com.au/h...y_battery.html
http://www.weincell.com/

2)....Using any battery of a higher voltage, then regulating them to 1.345v.
http://www.techlib.com/electronics/mercury.htm

Click the image to open in full size.

I'm not sure if a "voltage reference" chip would work.....the closest voltages are 1.2v, or there's a 1.2875v.
(I suspect in the bridge circuit, that the 1.55v silver oxide's might work straight-away, because they're just there to achieve a null, anyway.)

There may be some newer very-low dropout regulators to regulate a battery.
I do have some Vref ...TL431....LM385-1.235v....LM134 & 234.


help ??

=RR=
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Old 15th June 2008, 05:09 PM   #2
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It's quite easy to produce a suitable voltage for the majority of battery driven gear, you can drop an overvoltage battery or cell a few tenths of a volt using a series diode. You can use a zener or an LED depending on the exact voltage required.

Since different batteries have different discharge characteristics this may not result in an ideal output throughout.

You can assemble button cells into a tube to get excess voltage to drive a regulator.

Or you can arrange a supply from the mains.

This said, making the whole thing fit into some apparatus such as a camera, and be portable, and have a useful service life is another thing.

Sometimes it's just better to let the equipment go. I wouldn't be running a battery-driven valve radio receiver these days other than as a demo. Where can you buy a grid-bias battery?

w
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Old 15th June 2008, 09:00 PM   #3
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Thanks wakibaki.
It's not for a camera though.
The test gear uses the batteries. A "voltage potentiometer" used one cell, and the other unit is a "dc null meter" that uses two cells, center tapped in order to "zero" the needle on the meter.

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Old 1st July 2008, 06:45 PM   #4
Tahmid is offline Tahmid  Bangladesh
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Hi,
How about using a LED followed by a transistor?
The LEDs voltage drop would be the reference voltage, so output voltage would be Vf of LED - 0.6 (for transistor).
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Old 1st July 2008, 09:37 PM   #5
Tahmid is offline Tahmid  Bangladesh
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Hi,
If you use green LED, which has a voltage drop of approximately 2v, your reference voltage would be 2v. Now feed this to a transistor and at the output you get 2v - 0.6v(for transistor) = 1.4v.
The output voltage would remain 1.4v irrespective of input voltage, as long as the LED current is limited and the transistor can handle that input voltage.
This 1.4v should work where you need a 1.35v power source.
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Old 1st July 2008, 09:52 PM   #6
Eva is offline Eva  Spain
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Check out LP2951 micropower low dropout regulator. Typical quiescent current is 75uA (microamperes!) and output is adjustable down to 1.24V througn an external resistive divider. Input voltage may be as low as 2V for 1.24V output, and dropout at low currents is as low as 40mV.
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Old 1st July 2008, 09:57 PM   #7
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Using this circuite and 100ohms for r1 and 10 ohms for r2
would give you 1.24v + .12v = 1.36v or better yet use
a 50 ohm pot for r2 to varry the voltage from ~1.24v to 1.62V
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File Type: gif lm317t-voltage-regulation-circuit.gif (2.7 KB, 104 views)
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Old 1st July 2008, 10:05 PM   #8
Tahmid is offline Tahmid  Bangladesh
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Woody,
This circuit you provided would not work if input voltage is less than 4v as the minimum input voltage requirement of LM317 is 4v. But, it would work if redrabbit increases his input voltage from 2.25v as shown in the diagram to above 4v.
Thanks.
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Old 1st July 2008, 10:17 PM   #9
Tahmid is offline Tahmid  Bangladesh
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Hi,
I have used this circuit to power a digital thermometer which used a mercury cell.
In my opinion, this is the easiest circuit to fulfill redrabbit's requirement.
If you use 2SD882 transistor, you get an output current capability of >1.5A, so this would be pretty useful.
Voltage input can be upto 40v for 2SD882 and the output will remain 1.4v.
Voltage input can be as low as 2.8v.
Here, green LED must be used, since different LEDs have different voltage drops.
R3 could be given as per required according to the power requirement or can be omitted.
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File Type: jpg 1.4v power source.jpg (13.9 KB, 110 views)
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Old 1st July 2008, 10:22 PM   #10
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I did this for a Gossen meter --

http://www.tech-diy.com/gossen.htm

Linear Tech had a note which appeared in EDN of a very, very low dropout regulator -- this is going to be a big field owing to "energy scavenging".
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