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#1 |
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diyAudio Member
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Hello out there.
I have a specific problem for a non-typical audio problem. We want to use a piezo speaker for an alarm system an are restricted in size for the PCB and electrical components. But we need a lot of sound preasure in a specific frequency range of 3 - 4 kHz. Unfortunately there are not many piezo devices delivering more than 100dB in a distance of 10cm (~80 dB in 1m). My question is: "How Do I maximize the audiable SPL of a given piezo speaker for an alarm system?" 1. So the idea arose of adding a horn channel into the extruded plastic case to enhance the coupling of the acoustic impedance. 2. What audio waveform will generate most attention? For 1. I have the practical problem, that typical piezo drivers are not delivered with a thiele small parameter set while the horn simulation programs I know need these parameters. Any Ideas of how to make a rough simulation? Thanks in advance! Michael |
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#2 |
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diyAudio Member
Join Date: Jan 2006
Location: Johannesburg, South Africa
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I had one of those piezo sounders with two discs and an internal driver circuit. After years usage, it was damaged by a power surge, and the transistors died. I replaced them with transistors I had lying around (BC237, BC337) and the sound output was SIGNIFICANTLY louder after the repair. So they are not - by default - as loud as they can be.
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Steerpike's Toybox |
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#3 |
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Banned
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I think you are better to use a dedicated piezo alarm sounder with built in driver circuit rather than a piezo sounder and build your own driver. There are many of these. This one, for example, is 103dB @1 metre:- High Power Buzzer : Sounders : Maplin
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#4 |
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diyAudio Member
Join Date: Feb 2008
Location: Jackson,michigan
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basicly if want it LOUD you have to drive it with a higher voltage.a square wave is very anoying and the driver circuitry would be much less complicated.jer
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#5 |
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diyAudio Member
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@wakibaki
Thanks for the tip, but: My maximum diameter is 22mm with a maximum heigth of 10mm. If the device could be bigger, I would not have these problems ![]() Further more, I only have 2.4 - 3V from two AAA alkaline batteries. So I already made a driver circuit that is producing a square wave with 30Vpp. Most datasheets specify a maximum Amplitude arround 30V. Sofar no manufacturer could tell me what happens if I go beyond these limits. I assume eighter of the two effects a) brakedown of the dielectic barrier b) crack in the material due to mechanical stress. Increasing SPL will mean going far beyond these limits (Upp x2 will boost by 6dB). As we plan to construct a extruded plastic case where it is easy to incorporate a horn channel - this would be the preferred way. Any ideas on this?? Thanks a lot. |
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#6 |
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diyAudio Member
Join Date: Feb 2008
Location: Jackson,michigan
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well,the theory behind a horn is to couple the waves to open space more efficiently, by a transformation of impedence hence an acoustic transformer,there are lots of studies and dsicussions on this subject i am no expert on this and i'm still learning,however i do know the theory behind it.most of the design criteria i've read so far envolves known driver parameters and i have the same issues as you.what parameters do you use if you are not using a dynamic driver?but i can asure you this,by using a horn this will increase the efficency but by how much is determened by horn length ,throat size and flare rate.there are few programs out there for free that help to determin those demensions.i have a few of them but i have not spent enough time yet to learn them.i once as a kid built horn with frequency cutoff of 1000hz i remember the the throat was 1" square and about 6" to 8" long with a exponetial flare and i drove it with various sized p.m speakers of 1 1/2" to 4" in diameter it seemed to work ,but being 12 or 13 i did not have the equipment to fully test it.in my thinking (at the time)it was supposed to make the speaker sound better,WRONG,what went in came out.but what i do remember is that it helped the dispersion of the sound waves making it seem a little louder only i had no way to measure it.the formula i used was simple and was in a very old audio handbook i got from the school libary and think i still have it somewhere if i can find it i'll look it up and post it.i hope that helps you out. jer
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#7 |
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diyAudio Member
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What do I exactly need to calculate/optimize a horn?
As far as I understand a horn transforms the acoustic impedance that the driver sees (without horn) to a different one. In principle I could roughly estimate that the horn and piezo are fourpoles (one transforms voltage/current to preasure/velocity, the other preasure/velocity to preasure/velocity). Is there any tool that can roughly estimate a horns impedance without the driver? Thiele small parameteres will not be easy for a piezo with a small chamber arround it. But acoustic impedance shoult be not a big deal to measure. |
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#8 |
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diyAudio Member
Join Date: Feb 2008
Location: Jackson,michigan
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correct.that is the same problem i'm having also, as i want to use a horn with small electrostatic driver.and i have been searching for the answer (and only found 1 or 2 oline calculaters);if a piston(speaker) is moving back and forth x distance at y frequency with a surface area of z what is the sound pressure level in db. everybody mistakes that with power requirment and driver efficiancy i do not care about how much power is required i want to know if an object with z area is moving x at rate of y how loud is it. i believe (although im no math major)with those known factors one could determin the impedence and apply to a horn, as the flare rate is the transformation ratio and the length determens the cut off frequency.thats how i seem to understand it.if anyone knows more abuot this feel free to jump in anytime.do a search on math cad and you will find a guy named martin king whom has done some very exstensive reaserch on the subject and has written several programs in mathcad to detremin such factors.good luck. jer p.s. if you find more answers i would like to read about them,meanwhile if you can't find the caculators i've mentioned(if you can use them)i will post them for you,good luck!
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#9 |
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diyAudio Member
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As the piezo I plan using is already encapsulated (like a driver) and has an opening of aprox 2mm my naive approach would be taking a growth function for a horn and just creating a throat from 2mm to my max surface area possible.
I know there are different formula for hyperbolic, exponential, spherical etc. horn types. The questions I have are: 1. Does the shape of the horn (symmetric vs asymmetric) has a big influence on the impedance and thus the frequency response? 2. Can I (when yes, how can I) roughly calculate what the gain of a horn will be? 3. Is it possible to make a rough driver model for the piezo from mechanical dimensions? I know the diameter, the size of the preasure chamber, can weigth the piezo ceramic, maybe measure the exitation on a certain frequency. Thanks for your help! |
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#10 |
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diyAudio Member
Join Date: Feb 2008
Location: Jackson,michigan
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a horn will not add gain it only helps to couple the sound wave to the to the open area in other words ,it helps to disperse the sound waves into a larger spherical wave front rather than a smaller one reducing the the conical beaming effect in doing this it may seem louder off to the sides due to better dispersion.but it will not add any energy to make it louder.you can't get some thing for nothing.you can also use a horn to concentrate all of the energy to smaller spot thus lessening the dispersion into a narrower conical beam.is this what you mean?yes this can intensify the sound but by not much, at adegradation of dispersion which isn't what you want for an alram if you need it louder then the rule of thumb is for every doubling of equivelant drivers (each driven at the same power level as one driver is driven)equals an increase of 6db.so therefor 2 drivers =+6db,4 drivers =+12 db,8 drivers=+18db,16 driver+24db,and so on.does that help? jer
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