Stator material selection, preparation and contacts

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Hi Calvin, MJ

The problem is that we don't have a working theory. So the only thing we can do is guess about the conditions for this effect to occur. So far we have:

a) the panel should be a strip source (todo: define ratio h/w)
b) it only applies for frequencies with a wavelength that is short compared to the height h (todo: define ratio h/labda)
c) the working distance of the effect depends on panel height (todo: define h/d)

h = panel height
w = panel width
d = panel to microphone distance
labda = source wavelength

I took the liberty of doing some measurements on a nearly flat strip source: w=3.5cm, h=59cm (the middle strip of a Quad ESL treble panel). The strip is flanked by two neighboring strips, undriven, one on each side, which could be a source of vestigal baffeling, but it could also be argued that those are for the better part acoustically transparant. The total width of the panel is 19cm. Total height 65cm. So there is some vestigal baffeling, but IMO it can still be considered a line source.

Frequency domain: 2kHz to 25kHz.

Distances varying between 1cm and 2m.
I hope we can all agree that this setup satisfies the conditions mentioned above. Here's the result:

An externally hosted image should be here but it was not working when we last tested it.


Distances going from top to bottom: 1cm, 2cm, 5cm, 10cm, 25cm, 50cm, 1m, 1.5m and 2m. Other conditions: 42% relative humidity, 25 degrees Celcius. Panel suspended in air, center 1 meter above ground. Microphone at straight angle with panel surface and aligned with the center of the panel (on a professional stand with no interfering objects nearby).

There is some interesting stuff in the graphs (most likely related to interference). But most relevant to the discussion is that on no occasion did the output rise at any frequency with increased distance, except for a small anomaly when going from 1cm to 2cm distance above 23kHz.
The results speak for themselves and the conclusion is that the effect can not be observed under these conditions, and certainly not over a wide distance and frequency range.

MJ: I concur, and I've also never seen anything in sound theory that can explain it. Constructive and destructive interference is well documented for flat and curved panels, and as far as I know does not show this 'max SPL at a distance' effect. Now stereo could be a whole different ball game.


I'm open to suggestions.

regards,
Arend-Jan
 
Hello,
I bought a spray called Plasti-Dip today. I know brush application is better but the consistency was wrong and didn't have any solvents around. The spray covers well inside the holes. Its called Plasti-Dip has dielectric strength 1400V/mil, a spray on application 2-3mil thick while a brush 3-6mil thick. They also have something called liquid electric tape. This stuff is pretty easy to pick up, much cheaper and easier to get than Gylptal. I have 4 coats on one side of sample piece.

AJ
waiting for things to try... this effect is very intriguing. I can model what is going on by solving the pressure wave equation with Dirchilet boundary conditions. I will share the assumptions with you. If my assumptions are not too restrictive I will be able to predict on axis pressure in near and far zone. I will try to get this done ASAP, or maybe you have?
Bry
 
AJ

I think what your hearing is constructive interference with the other speaker.


Can you repeat the experiment with one speaker off? I was confused because you said that you were on axis. If you have two on then you have to be off axis with respect to the other one. If on axis means perpendicular distance away from the source. If we still see the rise in SPL with just one on, then we have to try to limit the other variables, the room, the quads baffle etc.

Take Care
Bryan
 
Hi Bryan,

Perhaps my post was not as clear as I hoped it would be. I'll clarify. It's a mono experiment (one panel) and it showed that SPL is decreasing with distance, which is the intuitive result e.g. what we experience in everyday life. The effect Calvin is talking about could not be demonstrated.

You mentioned modeling the wave equation. Do you have some special modeling software of are you talking about matlab or something similar? I always find modeling interesting so if you have something please tell us more about it.

Regarding the stator coating, I think you could do some flash testing if you have a step-up transformer. Just see if it holds or flashes thru the insulation. The usual cautions about high voltage apply etc.

regards,
Arend-Jan
 
Hi AJ,

That sounds more intuitive, thanks for clarifying. Maybe to see the effect that Calvin mentioned we need to consider a stereo setup.

For testing the coating I was going to buy a cheap step-up transformer and wire the primary end to a speaker terminal on my amplifier. I do not have, nor what to buy a power-supply. When school is back in session I will have more access to a good oscilloscope. Do you think this is a safe idea? The transformer will probable be 50:1 and I will just earth ground the center tab.

I spent much time modeling ESL's. The model goes like this

The Electrostatic Part:

1. Determine the forcing on the membrane
a. we need to find the electric field everywhere in between the plates. There are three regions of interest between the plates, air, mylar, air. In all three regions the electric scalar potential obeys Laplace’s equation.
b. I assume that we coat both sides of the mylar with graphite. I looked around and some just coat one side. If we coat just one side then the uncoated side will develop an induced surface charge density that is about two orders of magnitude smaller than the free charge we can do put on with the power supply. This means that the forces (F=qE) on the left and right side of the film are not equal. It seems that we can get more forcing on the membrane if we just coat both sides.

b. I do not have access to a scanner right now, I will scan over the derivation tonight. I think my girlfriend does, or I’ll just use a digital camera.

Mechanical Part

1. With the force density known, we can solve the damped inhomogeneous (forced) wave equation with clamped edges (Dirchilet conditions). The initial conditions don’t matter, since the membrane is forced. Right now I only care about the steady state solution (long time). However we do learn a lot about the performance by studying the transient part (we can send the speaker an impulsive voltage).
a. The solution to this partial differential equation will give us the amplitude response of the membrane.

b. It is important to consider the membrane damped since the air mass outweighs the membranes mass.


Acoustic Part
I only have the above two parts completed. Determining the pressure waves generated on axis is not to bad, off-axis things get a little hairy and may require numerical evaluation.


The software I like to use is mathematica, I used matlab for a little bit. Seems to me that mathematica is faster, has more options, can do almost anything, and has better user interface. I will use mathematica do write the simulation of all three parts.
Bryan
 
AJ
This is the derivation to find the force density acting on the membrane. I don’t have time now, but I will spell out the meaning of the parameters tomorrow and discuss the boundary conditions.

I saw your stretcher jig, looks like nice app of Newton’s laws. Any success using for curved panel?

Whoops file size is to big, let me get your email so I can send.
 
Hi Bryan,

Wow, you've been busy! I have a lot of questions (at this point it's not completely to me clear what your approach is) but I'll wait for your e-mail and see what you have done before I start shooting.

The standard way to model the behaviour of a transducer is to make up an electro-mechanical model and translate the mechanical parts into electrical parts using a transduction coefficient. Then you can calculate or simulate the behaviour in the electrical domain, but only on a macro scale. It is however very usefull and you can use it to calculate frequency response on and off axis, input impedance and lot's of other usefull stuff.

Where a different approach could become really interesting is if you do not make the regular assumptions and simplifications, but instead simulate the actual physical process, e.g. the diaphragm has physical dimensions and distributed mass and charge, it is restricted in it's movement near the sides, acoustical coupling between regions, non-even air load and non-uniform electrical field because of stator holes and edge effects, diaphragm tension and resonance modes(!), etc, etc, etc.

I suppose the diaphragm could be simulated with a distributed spring-mass model and using finite element analysis. I have been fiddle-farting around with that some time ago but chickened out.

With a model like that you would move the desing of an ESL to a whole new level! It could be a ticket to your 15 minutes of fame. (it might require a super computer to do the sim though :)

Okay, back to reality.
Some simple questions about your model that float around in my mind:
* do you model the diaphragm as constant voltage or constant charge? With constant charge (which is the better solution when it comes to ESLs), the electrical field would be pretty much Vsig/2d on a macro scale (the diaphragm would have to take on the potential of the electric field at that point).
* does your model incorporate the negative stiffness introduced by induced charge on the stators?

Quote:
If we coat just one side then the uncoated side will develop an induced surface charge density that is about two orders of magnitude smaller than the free charge we can do put on with the power supply.

This is an interesting topic by itself. How do you get to the induced surface charge of two orders of magnitude down? Is it something you simulated?

regards,
Arend-Jan
 
I wrote:

With constant charge (which is the better solution when it comes to ESLs), the electrical field would be pretty much Vsig/2d on a macro scale (the diaphragm would have to take on the potential of the electric field at that point).

I like to add to the above statement that this is only the voltage as imposed on the diaphragm by the electric field (the signal on the plates). The second component that causes the diaphragm voltage to vary is the charge on the diaphragm and the change in capacitance (w.r.t. the plates) with position.
 
Nevod,
In acoustic modelling the only parameters that are needed are bulk macroscopic variables (averages of microscopic fluctuations). Mass density fluctuations, volume, sound speed in air, and temperature. In linear acoustics we treat all physical parameters as small perturbations of the static undisturbed medium. If we were considering vibrations of crystal lattices then your right we would treat the atoms making up the solid as an array of coupled harmonic oscillators that are excited by phonons.
 
bshaw147
I mostly agree, but the science of acoustics isn't sorted out completely yet.

arend-jan
Your frequency response curves got me quite confused..
I don't see effects of interference of signals coming from different loactions on strip.

If you follow the Baxandall's article, at 1 cm, with given panel sizes, you'll get 10db/decade rolloff at ~30Hz, assuming current drive, and assuming that beginnig of rolloff if -3db, and a 20db/decade rolloff at 8.5kHz.

At 2m, 10db rolloff would begin at about 5.5kHz, 20db rolloff would be too far into high frequencies.

What I see is essentially a flat response, with the only non-flatness noticeable from 50cm, at LF, till 3kHz, it's somewhat too short to determine slope of rolloff. Of course, I don't know how the panel is actually driven above xformer - constant-current, constant-voltage, or constant-power. However, it's still quite logical that character of drive can't depend on listening distance. :) Or I just don't see something?

(By the way, if it wouldn't bother you much, can you get current response after transformer, so it would be possible to derive response for panel itself, without transformer?)
 
Hi AJ
Looking back at post 27...

1. Do you model the diaphragm as constant voltage or constant charge?
I modeled the diaphragm as having constant surface charge density in operation. In reality, as Streng's in-depth paper shows, charge will tend to move on the surface. This is bad if we are interested in creating a linear acoustic transducer. This is exactly why some designers choose high resistant coatings like graphite powder. Some designers (me included) add a very large value resistor in-line with the diaphragm contact as to oppose the flow of charges on the surface. It may take a little longer for the diaphragm to be in equilibrium with the bias power supply (t=RC). I don’t think it matters.

2. "The electrical field would be pretty much Vsig/2d on a macro scale (the diaphragm would have to take on the potential of the electric field at that point)."

If we ignore the fact that our stators have holes then yes, the electric field anywhere in between the plates is the above simple expression (parallel plate capacitor, where 2d is distance between plates and Vsig is the potential difference maintained between them). If you are familiar with Laplace's equation for determining the scalar electric potential you will see that I get the same thing in the notes I provided in the email. Once we have the potential determining the electric field is trivial, E=-grad (potential). Since the potential only varies in the z-direction (I am ref. my notes) this amounts to taking the derivative of the electric scalar potential with respect to the z spatial variable. You will see that it is simply a constant. Calculating the forces requires one more step. The electrostatic force acting on a charged body is just F=qE, instead I find force density so f=sigma*E, where f=Newtons/m^2 and sigma=charge (measured in Coulombs) per meter squared. As you realize we have a distribution of charge on both sides of the diaphragm, which implies that we have a force on the left and right side, adding will give the net force density acting on the diaphragm; this is what we are interested in. We need to actually take the average of the force densities acting on the left and right side. The reason is we have to remove the contribution of the force exerted on itself by itself. To understand this, ‘you can not stand in a basket and expect to pull yourself outside of it by pulling up on the handles above your head.’

Now, the big difference with coating one side as opposed to coating both sides is that the coated side is a free charge distribution while the uncoated side will develop an induced surface charge distribution; due entirely by the electric field polarizing the molecules in the film (stretching them and so establishing a dipole moment distribution). I have to look back at my notes when I was using the derived expressions and finding order of magnitude estimates for the free and bound charge distributions. I just re-did the calculation and they were on the same order of magnitude (10^-6 Coulombs/m^2). However, I still have to prove that they will always be of the same magnitude for different values of bias potential and drive potential (you call it Vsig). I am not sure of this right now, I will be tonight. The reason I am unsure is that I did this calculations with different values for the potentials and I did see an order of magnitude change. If you are ready I can share with you the force density when we coat just one side, its not that much more difficult then the first derivation. It just relies on theory of how electrostatic fields can polarize materials. All of this is in any standard college level Electromagnetism book (I recommend Griffiths Introduction to Electricity and Magnetism and the graduate version by Jackson).

If you want to get deep we can consider the electric field produced not by solid plates but by perforated ones. Jackson solves for the fields around a circular aperture. It involves specialty functions that are too esoteric for me. I think there may be a more “elegant” way to attack this problem. One of the nice things about electrostatics is that it is a linear theory, and thus obeys the principal of superposition (one of the deepest things I discovered in College). We know the field of a solid plate and we know the field that would be produced by a circular disk (everywhere) that is at the same potential as the solid plate, do you think we can just subtract the solid plate field from the disk field? I started to do this derivation and it’s pretty clean. Now we just have to sum over all the perforations, specific down to what pattern is used, i.e. 1/8” diameters on 3/16” staggered centers. I plan on finishing this sometime in the near future, but I must leave time to build my own ESLs :). I waited about five years to get building, putting the anal in analytics.

3. Does your model incorporate the negative stiffness introduced by induced charge on the stators?

If I understand your question correctly, this is hard to account for and I think its small potatoes for correcting the above force expression. I started to solve this problem; the only way I know how to tackle this one is to determine the Green's Function. To be extremely brief and do no justice to the theory of Greens functions.... A Green's function is particular solution we look for. It is the systems response due to a unit input to the system. Once you have the functional form of it you can solve almost any boundary value problem you can think with any kind of distribution of sources. Here our unit source is a point charge, somewhere between the plates. You can get the function by using the method of images; you will need an infinite number of image charges to satisfy the homogeneous boundary conditions of grounded plates. Now that we have the Green's Function we can go back to the original problem of a sheet of charge in between the plates and solve for the electric scalar potential. But, wait the problem is even more complicated in that the surface distribution depends on the shape of the diaphragm, which is known by solving the wave equation. But, to solve the wave equation you need the forcing, to know the forcing you need the potential. You see the problem is coupled you have to solve them together. Coupled partial differential equations are one of the hardest things to solve for in mathematical physics. The potential via Green's thm. is related to the just founded Green Function. All of this is in chapter 1 of Jackson's Electrodynamics book. The expressions are anything but tidy.

So I got my plates rolled into a nice arc, I will attach pictures shortly. I don’t have a digital camera but my girlfriend does. Today I worked on the frames for the panels. They are coming out very nicely. I learned a great an easy way to curve wood! Really gives it a professional look. All you do is take a wet paper towel and wrap the wood with it, then put in your microwave. Mine only needed 30-50 seconds; you have plenty of time to put the now compliant wood into whatever shape you like. I just made an arc, which parallels the plate’s arc. This will serve as my top and bottom pieces. If you never tried it, do it, you’ll love it. For bigger pieces you’ll need a steamer (or a big-A$$ microwave). Hope the above helps you. If you never studied electrodynamics or only just a little it really is worth all those late nights and early mornings. I would recommend mastering Intro to Electricity and Magnetism by Griffiths first then move on to the more rigorous and ambitious Jackson text.

Have you had any success with using your stretcher jig for curved tensioning? I was thinking that we could just tension the film when it is flat then with another jig compress the steel curved stators together. With a curved design we should only tension the film in one direction, this way our film will act as a continuum of violin strings. Do you have some thoughts you care to share on techniques for getting a uniform coating, film type, coating materials, and optimal methods?

Take Care,
Bryan Shaw
Bjs2@njit.edu
 
AJ,
Believe it or not I did manage to forget something; you expressed interests in seeing a computer simulation. My coding is nothing special and ill probably lose my hair trying...I was comp-sci major when i first when to school, then i left the dept. to study math. I love Lab-View, makes writing programs that have to interface to other devices extremely straight-forward (except for the occasional proprietary stuff). Anyway, getting off subject. Mathematic a, would be what i would use to write up the sim.


Imagine seeing what your music looks like in your room. Of course our model makes a few assumptions. Did you catch mine in the notes; I only evaluate the force density at the average position of the membrane. This avoids that coupled problem I mentioned earlier. Believe it or not, I don’t think that this will hurt us any when we assume that the forcing has only a time-dependence, uniform in space. We usually find the solution when the drive voltage signal only contains one frequency and we do a little Fourier analysis to find the solution for noise, basically. The time average of the amplitude response to just one frequency component is dead-center, which is where we evaluate the force. You can look at the coupled scenario, made me too queasy. Your earlier comment of using some kind of FEM routine wont be necessary since the solution for the damped forced wave equation with clamped edges is well known, and can be visualized nicely. I suppose each element would be a differential area element of the film whose motion is governed by the simple harmonic oscillator (mx..=-kx x..= second order time derivative of amplitude, should include a damping term on RHS proportional to Beta*x.) Having these models connect with the acoustic routine is where all the fun will happen...

Take Care,
Bryan
 
Nevod said:
arend-jan
Your frequency response curves got me quite confused..
I don't see effects of interference of signals coming from different loactions on strip.

If you follow the Baxandall's article, at 1 cm, with given panel sizes, you'll get 10db/decade rolloff at ~30Hz, assuming current drive, and assuming that beginnig of rolloff if -3db, and a 20db/decade rolloff at 8.5kHz.

In the text accompanying fig 3.32 in the baxandall article he also says that it's not acurate until r > 2*h. So we can't use it at a distance smaller than 1 ~ 1.5m in which case we expect the first dip around 9-10 kHz, followed by an inclination which is indeed the case.

At shorter distances you can clearly see the dips around 3.2 kHz and 4.5kHz, I assume as a result of destructive interference.


(By the way, if it wouldn't bother you much, can you get current response after transformer, so it would be possible to derive response for panel itself, without transformer?)

I don't mind if you can tell me an easy way to do that without the risk of blowing up my audio board.
 
Hi Bryan,

thanks for your response. Before I forget to mention it, I did not receive your model or notes by e-mail.

You address so many point that I think it's easier and clearer if I quote you and comment on it.

This is exactly why some designers choose high resistant coatings like graphite powder. Some designers (me included) add a very large value resistor in-line with the diaphragm contact as to oppose the flow of charges on the surface. It may take a little longer for the diaphragm to be in equilibrium with the bias power supply (t=RC). I don’t think it matters.

I would not consider graphite high S/R when it comes to full range ESLs. You have to consider charge movements as a result of membrane vibrations (=> voltage gradient). Streng deduces that harmonic distortion does not come into play significantly for S/R of 10^9 or higher. You can't go that high with graphite.
A resistor in the HT line will keep the total charge on the diaphragm more or less constant, but it can not prevent charge movement on the diaphragm. So it's not an equal solution.

As you realize we have a distribution of charge on both sides of the diaphragm, which implies that we have a force on the left and right side, adding will give the net force density acting on the diaphragm; this is what we are interested in. We need to actually take the average of the force densities acting on the left and right side. The reason is we have to remove the contribution of the force exerted on itself by itself.

If we assume for the moment that there is a charge on both sides of the diaphragm, then I agree that we can simply add the charge on both sides (with awareness of sign) and work with the total charge since we are talking about a linear system and the distance of the charge on both sides is in the micron range, which is next to nothing on the scale of the stator to stator distance. If we like to work with the charges seperated then we can simply add the forces on both sides of the diaphragm. I don't see a 'force excerting upon itself' here. Maybe if I had your notes this would be clearer.


We know the field of a solid plate and we know the field that would be produced by a circular disk (everywhere) that is at the same potential as the solid plate, do you think we can just subtract the solid plate field from the disk field?

That's an interesting question. At first glance I'd say yes, but I have to think about it a bit more before I commit to it.

3. Does your model incorporate the negative stiffness introduced by induced charge on the stators?

If I understand your question correctly, this is hard to account for and I think its small potatoes for correcting the above force expression.

If we take the charge on the diaphragm to be constant then the induced charge on the stators is contant and it becomes really simple: Fme = -2*x*e0*A*Vpol^2 / d^3
Fortunately this is expression is linear with the diaphragm displacement 'x' so no trouble there. The minus sign indicates that it is actually enforcing the deflection of the diaphragm. The force is the same order of magnitude as the drive force so we can't ignore it. If the charge is not constant then the force becomes highly non linear.

Have you had any success with using your stretcher jig for curved tensioning? ... Do you have some thoughts you care to share on techniques for getting a uniform coating, film type, coating materials, and optimal methods?

I have not tried to build a curved stator with the stretching jig yet. If I wanted to I'd have to make it bigger and add more clamps on the short sides. I'm currently experimenting with spray coating, but excellent results can be had with wipe-on coating, for example Martin-Jan's EC coating (recommended). Hostaphan film can be had here. Martin-Jan also sells a 6 micron Mylar (presumable tensilised) which is pretty good.

Your earlier comment of using some kind of FEM routine wont be necessary since the solution for the damped forced wave equation with clamped edges is well known, and can be visualized nicely. I suppose each element would be a differential area element of the film whose motion is governed by the simple harmonic oscillator (mx..=-kx x..= second order time derivative of amplitude, should include a damping term on RHS proportional to Beta*x.)

okay agreed. An coupled harmonic oscillator model is actually what I had in mind. I would not asume too much about the diaphragm behaving well damped (because we know it's not, at least not over the full frequency range). Real world ESLs have resonances all over the place. It would be nice if the model allows us to introduce localised deviations (like different hole patterns) etc. to play with local air loading to surpress resonance modes for example.

I found a really nice differential expression on page two of this document by Edo Hulsebos. I think you will like it.

Regards,
Arend-Jan
 
ESL simulator

As a result of this discussion I decided to build a macro-simulator for electrostatic loudspeakers. It can calculate the frequency response for flat, rectangular ESL panels. You can freely choose the position of the listener as well.

It is web based, and 100% free :) Just punch in your numbers and go! You can find it on the link below.

ESL simulator

Enjoy,

Arend-Jan
 
Hi Bryan,

I resent the email, with the pics.
Your suggestion on not using graphite will be applied. I never was comfortable with rubbing it in anyway, at least your can measure its resistance in several places to verify that it is uniformish.

S/R, stands for? (signal/resistance?)

Your right, the large resistor keeps total charge pretty much steady but does not keep the charge density steady. The link you provided had some nice solutions that i will probably give a try.

When you say that your numerical model would consider coupled springs, do you mean springs attached vertical up and down the film and springs that run normal to the films surface, or both. It is a really good idea to do this. We can model hard surfaces that will reflect the pressure waves as springs that have a very large spring constant (infinite even). Spring constant, from Hooke's Law says that the restoring force a spring would feel as it is displaced by a displacement of x is just F=-kx, where k is the spring constant. I’m sure we can model the air the same way. For any kind of accuracy will need a lot of springs, and hence computations. It may take a long time to run it. If we take the limit of some kind of continuum of springs than our equations may look similar to equations you would see in the linear theory of acoustics. This may give a good way to check our routine. I don’t see the film being displaced vertically that much. This would help reduce the dimensions of the problem and keep computation time shorter.

The equation on page two of Hulsebos includes an electrostatic part (to express the forcing) a mechanical part (this was the wave equation, last 3 terms of his equation), and an acoustic part. His second term includes the effect that the films charge will induce a stator charge. He does include a damping of the film by including his very last term.

Take Care,
Bryan
 
Stator material

Calvin wrote: "ESLs are high impedance devices."

Would carbon fibre be suitable for stator or is the conductivity too low?

I love cf and have done "some other than audio stuff" with it. If cf is possible material for stator it would open amazing possibilities!

I'm starting to build small hybrid with stator in two sections, going to make frame from fibreglass and just started to think about conductivity of cf and can it be used in this project...
 
Hi,

actually I don´t know if CF could be a good material for stators.
From the viewpoint of conductivity it would, but conductivity of a stator is not the point to worry about with ´standard´ conductors having less than say 1kOhms of resistance.
The stator´s behaviour under HV-conditions has to be investigated.
(There have been accidents with helicopter rotor flaps beeing destroyed by lightnings. ESL-arcing is the same on a minor scale) There will always be arcing since You operate a ESL close to the field breakdown limits of air. How does carbon behave under this condition? I am afraid, that it ages quickly and might even be destroyed. Even if insulated impurities within the material might lead to accelerated aging. Besides beeing a strong but lightweight material I can´t see any advantages for carbon against Steel, Copper or Aluminium. Cost, Handling and probably Performance will be inferior.

jauu
Calvin
 
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