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#1 |
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diyAudio Member
Join Date: Sep 2005
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Maybe you can help, On the circuit there is a 2R2 resistor on the source of the fet... WHY? what voltages does it see? which currents flow through it... how would its size be determined, if I change bias etc in the circuit... From what I see the 100k pot sets up a voltage divider to provide x volts DC on the gate to enable the fet to conduct from drain to source... The signal in AC is also put to the gate and a small AC portion is added to the Drain which is allready at a potential of 6.45VDC in order to reach the 168mA,DC on the drain resistor. At the point between the resistor and drain, I can only see how a small fraction of the signal voltage gets here... Does this small bit also flow trough the Drain to source? How do I calculate voltage/current gain? Where is the amplification? what am I missing? Uncle Nelson, how about a low voltage zen headphone tutorial...aimed at the beginner... In the attached circuit the only part that gets realy hot 60+C is the 2W resistor, I used reasonbly small sinks on the fets themselves. So its a very cheap/safe/easy intro into the wonderfull world and sound of Mosfets. |
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#2 |
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Formerly "jh6you". R.I.P.
Join Date: Jul 2006
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IRF610 is a current amplifier, being controlled by the input AC Vgs.
Based on the amplified current, the voltage gain is achieved by the resistors of 33 and 2R2--~33/2R2. In addition, 2R2 works also for a negative feedback. |
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#3 |
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diyAudio Member
Join Date: Sep 2005
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WHat happens when the 2R2 resistor =0R
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#4 |
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The one and only
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You get about 5 times more gain, trading away some linearity.
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#5 |
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diyAudio Member
Join Date: Sep 2005
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Curse at the devil over your coffee, and he posts in your thread...
Nelson, if it wasn't for this little amp, I would not believe myself capable of building one of your amps... I am now a student of your school. I see some of your circuits do connect to ground there but seems to have some gain setting method through a trimpot over input and output caps. Actualy I think I'm makeing progress trying to design another version with double the supply voltage etc... to test if I got the fundemental concepts.... PS, if the 2R2 =33R would it mean unity voltage gain? First goal is to go from 168mA bias to 400mA wich represents 4.8Watt dissipation over the drain resistor of 30R. with 24v supply, I should be looking at 12V on the drain? No idea what the fet would be dissipateing...I will hide behind a cushion (the only word ohter than fashion to end on -shion). The current circuit suggests it would be less than the Resistor. |
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