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#1 |
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diyAudio Member
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Ok, 2 questions. I've searched and searched and haven't found a great explaination about how to adjust ac current gain on an aleph 2. Most explainations tell what to set it to, not how to set it. Anyway, if someone could explain this to me, that'd be great, or at least give me a link that says how to adjust it. Some info, i'm going to be using 16 outputs per channel of irp240.
i'm using 1 ohm source resistors and for the output resistors i'm using mra-12 mills .22 ohm x3 in parallel. i'm gonna set the bias w/ a 100k pot for r19, and i may have a switch that can switch between 2 or 3 different parallel resistors eventually to have the bias set for fall/summer/winter settings (i can use a dpdt switch to adjust ac current gain as needed as well, but i need to know how to adjust ac current gain) also, i'm using ztx450's, can someone look at the layout and make sure that they are the correct orientation? thanks! -Matthew K. Olson |
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#2 |
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diyAudio Member
Join Date: Aug 2003
Location: Long Island, New York
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Matt,
It is difficult to tell from the picture. If you look directly at the flat side of the transistor, the lead to the left is the emitter. Here is the PDF file for the ZTX450.
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----------------------------------------------- It's Alive, It's Alive! Kilowattski |
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#3 |
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diyAudio Member
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In the pic, you are looking at the roundish side of the transistor w/ the ztx printed on it. The flat side doesn't have anything printed on it. Seems to me this is correct. Email me and i'll send you the real pic.
![]() -Matthew K. Olson |
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#4 |
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diyAudio Member
Join Date: Sep 2003
Location: Paris - France
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Mattyo5,
For the ZTX450 it seams to me they are OK. Refer to the picture... Regards. Alain. |
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#5 |
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diyAudio Member
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i've seen the pic, the "back" is the curved part and is where ZTX 450 is printed and is the face that is facing us in the pic I posted. i think its correct
![]() -Matthew K. Olson |
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#6 |
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diyAudio Moderator
Join Date: Jan 2003
Location: Belgium
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Adjustment of Aleph current source can be found here .
Read on page 3: "In any case, to achieve this 50%..." Also, look at the WIKI -> AlephX for a more practical example. /Hugo
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Toothpaste is bad for the teeth; it’s too sweet. |
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#7 |
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diyAudio Member
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Ok, very cool. THATS the link i was looking for. Lets see if i get this straight.
i measure voltages across resistors voltage across one source resistor VRS voltage across output resistors VRO and in the case of aleph 2, i adjust r21 to get proper ac current gain.... so the math VRO/ (output resistance) = x amount of current VRS/ (source resistance) = y amount of current [1 - (y/x)] x 100 = ac current gain percentage an example w/ my numbers might be: .05v / .07 ohms = .71A .05v/ (16 fets total, and 1 ohm source resistors = .0625 ohms) = .8A .8A/.71A = 110% ac current gain ...yikes ...hope i don't measure .05 v across all those resistors! is this math theoretically correct though, assuming i measured .05v across those resistors...which i didn't ?? thanks guys, just trying to clarify things for the morons like me ![]() -Matthew K. Olson |
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#8 |
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diyAudio Member
Join Date: Aug 2001
Location: Ingolstadt Germany
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Hi,
that´s right although in this case you get more current out than you put in Don´t forget to measure AC-Current. William
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een ooievaar is geen konijn want zijn oren zijn te klein! |
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#9 |
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diyAudio Member
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Ok, right, i gotta have my multimeter set to ac volts. Also, do I have a signal playing , like 1khz sine when i do this?
-Matthew K. Olson |
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#10 | |
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diyAudio Moderator
Join Date: Jan 2003
Location: Belgium
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Quote:
![]() Yes 1K will do. Only, it's such an annoying tune. I prefer lower like 100Hz. /Hugo
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Toothpaste is bad for the teeth; it’s too sweet. |
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