Capacitor Multipler

ralf · 1st January 2002, 08:21 PM

Hi,

has anyone experience with this thing?

I have build one for my SOZ, and - you can hear no hum or buzz at all!

when i use a conventional Capacitors PS of about 400000 !!uf per channel a small buzz is hearable!!

BUT: the TO3`s get extremly hot at about 20 volts per rail (90 degrees !!), and i want to increase the voltage to about 60 V per rail.

I think, with increasing the wattage of the SOZ and the Capacity Multipler i need to build a case for the amp as big as a refrigerator.

Nelson Pass · 2nd January 2002, 07:59 PM

Yes, capacitor multipliers work great.

On the dissipation side, if you are using a Mosfet, then
the wattage will be the Vgs (about 4 volts) times the
current, and that will be all of it.

If you are using a bipolar, then the drop across the
device will depend on the resistance you have on the
base. If the Collector-Emitter voltage is much more than
say 2 volts, you can reduce it by reducing the value of the
filter resistor.

1st January 2002, 08:21 PM	#1
ralf diyAudio Member Join Date: Dec 2001 Location: Germany	Capacitor Multipler Hi, has anyone experience with this thing? I have build one for my SOZ, and - you can hear no hum or buzz at all! when i use a conventional Capacitors PS of about 400000 !!uf per channel a small buzz is hearable!! BUT: the TO3`s get extremly hot at about 20 volts per rail (90 degrees !!), and i want to increase the voltage to about 60 V per rail. I think, with increasing the wattage of the SOZ and the Capacity Multipler i need to build a case for the amp as big as a refrigerator.

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2nd January 2002, 07:59 PM	#2
Nelson Pass The one and only Join Date: Mar 2001	Yes, capacitor multipliers work great. On the dissipation side, if you are using a Mosfet, then the wattage will be the Vgs (about 4 volts) times the current, and that will be all of it. If you are using a bipolar, then the drop across the device will depend on the resistance you have on the base. If the Collector-Emitter voltage is much more than say 2 volts, you can reduce it by reducing the value of the filter resistor.