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#1 |
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diyAudio Member
Join Date: Mar 2002
Location: n/a
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Hey all.
I'm currently applying power to my F3 boards, and I'm having trouble setting the current source. I understand that the percentage is supposed to be the ratio of current through the output resistor to the ratio through the aleph resitors. So what I've got, I measuring the AC voltage across resistors R6/R7/R8 (which make 0.4 ohm), and the output resistor R9 (0.47 ohm). Here's what I get : drop across r6/r7/r8 = 0.206 V 0.4 / 0.206 = 1.94 A drop across r9 = 0.35 V 0.47 / 0.35 = 1.35 A 1.94/1.35 *100 = 140 % !!!!!!!! That's not right ... No matter what I set P2 to, the current through the aleph resistors is alway greater than what's going though the output resistor. Any idea where I may have gone wrong ? |
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#2 |
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diyAudio Member
Join Date: Apr 2002
Location: Washington State
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Should'nt the voltage drop across R6,7,8 be .66 volts, the emitter base junction of Q4?
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#3 |
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diyAudio Member
Join Date: Mar 2002
Location: n/a
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Sorry everyone.
Please delete this thread, or make it a sticky, as a permanent reminder of Ohm's law. My calcs should have been along the lines of 0.204 (V)/0.4 (ohms), rather than 0.4 / .204 ..... *smacks head* |
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