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Old 13th November 2001, 08:12 PM   #1
jduncan is offline jduncan  United States
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I've started working on the Aleph 4 and I had one particular question... I'm guessing that this is VERY trivial but I couldn't come up with the solution at first glance.

I see that each channel dissipates approx. 288W (48V rails so 96 * 3 = 288W). How is the max power output figure of 100W calculated? I couldn't quite workout how to get this.

Any help would be greatly appreciated!
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Old 14th November 2001, 12:06 PM   #2
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take the supply voltage 48 volts minus the voltage drop caused by the fets and source resistors (approx. 4-5 volts).
After that itīs simple 44 / sqrt(2) = Veff.
Veff^2 / 8 = power into 8 Ohms (115 Watts in this case) For power into 4 Ohms you need to know the max. current available.

william
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Old 14th November 2001, 08:37 PM   #3
jduncan is offline jduncan  United States
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ok....

Does the maximum voltage at the output point to calculate this take into account the drop over the output transistors and source resistors and the negative rail too?

I'm confused here just looking at the schematic in this case.

Also, from everything I've read, because this is a single-ended design, the power into lower loads only decreases instead of increasing as happens with push-pull designs.

How does that occur here?
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Old 14th November 2001, 09:06 PM   #4
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Yes, the 4-5 volt I mentioned are the volstage drop over the output fets and the source resistors.

Also, from everything I've read, because this is a single-ended design, the power into lower loads only decreases instead of increasing as happens with push-pull designs.

How does that occur here? [/B][/QUOTE]

it doesnīt. Look for example at the Aleph 5. Pass claim a max output of 30volts (i.e 34V supply voltage -4V drop) and 8A. Theoretically this gives about 56 watts into 8 ohms at 2.65A eff. and 112 watts into 4 Ohms at 5,3A eff Max power should be 30 x 8 /2 = 120 watts at 3.75 Ohms. In practice the supply voltage will go down (unless regulated) so the gain in power into lower impedances wonīt be that big.(claim is 90 W into 4 Ohms)

hope this helps,

william
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Old 14th November 2001, 09:10 PM   #5
jduncan is offline jduncan  United States
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But the Aleph 5 has a claimed 100Wpc output into both 8 AND 4 ohms....it doesn't go up.....

So what about the drop across the FETs and source resistors in the current source?
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Old 14th November 2001, 09:22 PM   #6
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mmmm.......

my owners manual says 60 watts @ 8Ohms and 90 watts @ 4 Ohms for 1% distortion and a max. output of 30V/8A

The voltage drop is the 4-5V I mentioned before. The voltage drop depends on the value of Vgs, the source resistor, Rds on and the current thats going through.

william
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Old 14th November 2001, 09:57 PM   #7
jduncan is offline jduncan  United States
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sorry I meant the Aleph 4 has 100wpc into both 8 and 4 ohms
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Old 14th November 2001, 10:46 PM   #8
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sorry to disagree again but I canīt find a power claim into 4 Ohms for the aleph4. Only 100Watts @ 8 Ohms
With a 950VA transformer for both channels (estimated from the primary fuse) it should be aprox. 165 Watts into 4 ohms.

william
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Old 14th November 2001, 11:23 PM   #9
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The Aleph 4 was designed to output almost the same power into 4ohms as into 8ohms just with quite a bit more distortion.

[Edited by AudioFreak on 11-14-2001 at 05:43 PM]
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Old 15th November 2001, 12:25 AM   #10
jduncan is offline jduncan  United States
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right.... It definitely doesnt put MORE power out into 4 ohms...a non single-ended design is needed to do that right?
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