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#1 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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Is anyone aware of a diode that will drop ~1.7V and that can pass 60mA (so probably no LEDs)?
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#2 |
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diyAudio Member
Join Date: Apr 2006
Location: Minnesota
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What do you really want? In other words, can you just put a silicon diode in series with a 17 ohm resistor? In other words, could you use two diodes in series?
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#3 |
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diyAudio Moderator Emeritus
Join Date: Jan 2005
Location: Pennsylvania
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Why not just use 2 or 3 diodes in series? Or if you need a power diode that can pass a lot of current you can use a transistor and a diode. Connect the diode between the collector and base of an npn bjt and it will drop 0.7V and provide current to the base. The base emitter junction will drop another 0.6-0.7V. Most of the current should be handled by the transistor.
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Brian |
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#4 |
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diyAudio Member
Join Date: Sep 2004
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Parallel 4 LED's maybe?
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#5 |
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diyAudio Member
Join Date: Jul 2006
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....There's a lot of high current LED's out there nowadays. I used to work at hp/Agilent and they (used) to have the market cornered on high power LED's. They sold off the LED business to Philips. It's called LumiLEDS Here's a link to some high power BRIGHT stuff. I didn't check Vf, but the power's there. <http://www.lumileds.com/pdfs/DS05.pdf>
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".........These go to eleven" |
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#6 |
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diyAudio Member
Join Date: Feb 2004
Location: Silicon Valley
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Who needs a diode? Use a VBE multiplier made from an appropriate transistor.
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#7 | |||
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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Quote:
Quote:
Quote:
Thanks |
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#8 | |
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diyAudio Member
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Quote:
... err... parallelling LEDs (or diodes) does not change the conduction voltage (but it does increase the current handling capability).. Jan Didden
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/Another new issue: Linear Audio Volume 3! |
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#9 | |
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diyAudio Member
Join Date: Sep 2004
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Hi Jan,
Quote:
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#10 | |
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diyAudio Member
Join Date: Jul 2006
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Geek responded to janneman:
Quote:
In theory and maybe in practice, the Vf is more closely matched. I'd recommend using ballast/balancing resistors to equalise the current sharing. This is probably a pointless statement for this issue, as there isn't enough room to do the Quad-LED approach, but I had had to chime about the 4 parallel LED's not being a perfect solution.
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".........These go to eleven" |
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