Energy Loss - Page 11

kvholio · 9th September 2006, 06:58 PM

I like a good headache once in a while.
Darn ,Chris, now i missed my flight !

Cheers,

Klaas

SY · 9th September 2006, 09:56 PM

Jeez, guys, this is a simple problem in statics. Why are you trying to overthink it?

poobah · 9th September 2006, 10:01 PM

Well I say no R... no L... no tickee... no laundly

Let's hear it...

SY · 9th September 2006, 10:14 PM

Why do you need R or L? It's a statics problem.

anatech · 9th September 2006, 10:21 PM

Hi SY,
Well, statistically speaking, it's not a problem for me. Sounds like a calculus deal anyway.

I caught the last flight out. I had my ticky and left with my laundry.

I need my L and R for stereo, I have no idea what you're listening to.

-Chris

poobah · 9th September 2006, 10:22 PM

You have to have a vehicle/reason/method/excuse for energy to leave the system... that means store it, L, or burn it, R.

You can just simply state that charge moved through a gradient takes work... and that does solve the whole thing nicely enough without any consideration of an R. But R is implied when the work word comes up...

The whole thing is a sucker punch trick.

anatech · 9th September 2006, 10:31 PM

Hi poobah,
We all know energy is lost big time in the real world. There is a spark, heat, noise and sometimes the parts get mildly warm.

It's best to accept reality rather than argue a nonexistent theoretical situation. Our theories were developed through observation of our real world, of course the theories fall down in a different situatuon.

Me, I'm going to help prepare dinner. In my plane, I'm hungry.

-Chris

pinkmouse · 9th September 2006, 10:37 PM

How did I miss this thread?

Anyway, I'm simple and not a mathematician, so my attempt at an explanation is too. Imagine two gas bottles, identical in size, one filled with gas at 10 PSI, one with a vacuum. Connect them together, and you have two bottles filled at 5 PSI. Now, use that gas pressure to do work, say, blowing up balloons in a vacuum. The two bottles will inflate as many balloons as the one. Where's the problem?

poobah · 9th September 2006, 10:39 PM

here

Quote:

After connecting the charged and the uncharged capacitor electromagnetic oscillations will occur in the circuit consisting of the capacitor and the wires (having a small inductance).

In case of supraconductive wires (with no resistance) the oscillation will go on for a while and will be damped only by the radiation, and the electromagnetic wave will have the energy missing in the circuit.

In reality the resistance of the wires converts the electromagnetic energy into heat.

poobah · 9th September 2006, 10:43 PM

Chris,

That's what I'm saying! The circuit has to have some R or L.

The sucker part is assuming it doesn't.

9th September 2006, 09:56 PM	#102
SY Tetsujin diyAudio Moderator Join Date: Oct 2002 Location: Austin, TX	Jeez, guys, this is a simple problem in statics. Why are you trying to overthink it? __________________ "We all feel like that, Reggie, now and then, especially when Spring is upon us, but few of us would care to put it on our cards." — Sir Archibald Clerk-Kerr

9th September 2006, 10:14 PM	#104
SY Tetsujin diyAudio Moderator Join Date: Oct 2002 Location: Austin, TX	Why do you need R or L? It's a statics problem. __________________ "We all feel like that, Reggie, now and then, especially when Spring is upon us, but few of us would care to put it on our cards." — Sir Archibald Clerk-Kerr

9th September 2006, 10:37 PM	#108
pinkmouse diyAudio Moderator Join Date: Apr 2002 Location: Chatham, England	How did I miss this thread? Anyway, I'm simple and not a mathematician, so my attempt at an explanation is too. Imagine two gas bottles, identical in size, one filled with gas at 10 PSI, one with a vacuum. Connect them together, and you have two bottles filled at 5 PSI. Now, use that gas pressure to do work, say, blowing up balloons in a vacuum. The two bottles will inflate as many balloons as the one. Where's the problem? __________________ Al There is science, logic, reason; there is thought verified by experience. And then there is California. Edward Abbey

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9th September 2006, 06:58 PM	#101
kvholio diyAudio Member Join Date: Jul 2005 Location: leeuwarden	I like a good headache once in a while. Darn ,Chris, now i missed my flight ! Cheers, Klaas

9th September 2006, 10:01 PM	#103
poobah diyAudio Member Join Date: Nov 2005	Well I say no R... no L... no tickee... no laundly Let's hear it...

9th September 2006, 10:21 PM	#105
anatech diyAudio Moderator Join Date: Jun 2004 Location: Georgetown, On	Hi SY, Well, statistically speaking, it's not a problem for me. Sounds like a calculus deal anyway. I caught the last flight out. I had my ticky and left with my laundry. I need my L and R for stereo, I have no idea what you're listening to. -Chris

9th September 2006, 10:22 PM	#106
poobah diyAudio Member Join Date: Nov 2005	You have to have a vehicle/reason/method/excuse for energy to leave the system... that means store it, L, or burn it, R. You can just simply state that charge moved through a gradient takes work... and that does solve the whole thing nicely enough without any consideration of an R. But R is implied when the work word comes up... The whole thing is a sucker punch trick.

9th September 2006, 10:31 PM	#107
anatech diyAudio Moderator Join Date: Jun 2004 Location: Georgetown, On	Hi poobah, We all know energy is lost big time in the real world. There is a spark, heat, noise and sometimes the parts get mildly warm. It's best to accept reality rather than argue a nonexistent theoretical situation. Our theories were developed through observation of our real world, of course the theories fall down in a different situatuon. Me, I'm going to help prepare dinner. In my plane, I'm hungry. -Chris

9th September 2006, 10:43 PM	#110
poobah diyAudio Member Join Date: Nov 2005	Chris, That's what I'm saying! The circuit has to have some R or L. The sucker part is assuming it doesn't.

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