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Old 31st July 2006, 12:04 AM   #1
jarthel is offline jarthel  Australia
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Default IEC AC Filter

can someone please tell me if the ground output of this filter is derived ground and the AC ground is left hanging?

Here's the schmetic: http://www.cor.com/Series/IEC/EEAEEB...-Schematic.gif

If it is derived ground, does that mean I cannot connect the metal chassis to this derived ground. I've always grounded the metal chassis to AC ground for safety.

Thank you.

ps. I haven't bought the filter yet.
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Old 31st July 2006, 12:14 AM   #2
poobah is offline poobah  United States
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That ground is connected straight through. The identical symbols imply an identical node (wire). The ground is not "derived".

You will also find those to be a nice device and very cost effective.

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Old 31st July 2006, 12:24 AM   #3
jarthel is offline jarthel  Australia
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Quote:
Originally posted by poobah
That ground is connected straight through. The identical symbols imply an identical node (wire). The ground is not "derived".

You will also find those to be a nice device and very cost effective.


thanks for the help
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Old 31st July 2006, 01:19 AM   #4
poobah is offline poobah  United States
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Keep in mind, I've heard plenty of comments around here that those things will "constrict" your sound... pure B.S. Make sure you have an adequate current rating in the device you choose.

The rectifiers in your PSU will make some RF (hash) of their own of course, but YOU control that. The power line is a different story.
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Old 31st July 2006, 01:15 PM   #5
AndrewT is offline AndrewT  Scotland
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Hi,
re post1:- what is that resistor for?
To discharge the three tiny capacitors?

You can buy chassis mount version that range from about 1A to 6A.

You can also build your own.
But, since you are working with mains voltage you must know what you are doing and how to protect users and maintenance technicians.
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Old 31st July 2006, 01:25 PM   #6
SY is offline SY  United States
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Quote:
what is that resistor for?
WAG here, but I'd wager that it's there in case the line (source) circuit is disconnected.
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Old 4th August 2006, 03:48 PM   #7
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Default Resistor?

Yes, it would bleed stored charge off the caps for safety’s sake, in case connections to the load and line are both opened. My guess is that the shunt resistor also figures into the damping of the resonance(s) created by the shunt Cs and series Ls. Neither the line nor the load will have known or controlled impedances and can offer no guarantee of damping of resonances by themselves. In particular, the line side impedance could be dominated by high series inductive reactance, thereby contributing only reactance to the resonant mix. The resistor might then set a worst-case maximum value of Q.
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