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#1 |
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diyAudio Member
Join Date: Apr 2006
Location: Shenzhen
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Hi everyone!!!
I am new to electronics, I got a question as below. As the attached sch shows, the 128k and 64k input signal was connected with a resistor and capacitor, then a potentiometer. What do they do? I think they just match the impedance with the IC mc4053. Thank you very much for your opinions!!! |
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
is the 128K and 64K the bit rate? I would expect to see 128kb or 128kb/s. C100 & C103 look like a DC block from either direction. R100 & R101 could be stability loading.
__________________
regards Andrew T. |
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#3 |
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diyAudio Member
Join Date: Apr 2006
Location: Shenzhen
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the 128k and 64k mean the input signal: 128kHz and 64kHz square or sine wave or else.
what does your "stability loading" mean? could you tell me more or give me a related web? thank u :-)
__________________
this is tabooes~~ |
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#4 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
some opamps don't like capacitance on their outputs. A little resistance isolates the capacitance and maintains the phase margin. Have a look at WJung's site for lots of very detailed and absolutely accurate info on opamps. www.waltjung.org look at library/ classic for a listing It might be here. http://waltjung.org/PDFs/ADI_2002_Se..._Drivers_I.pdf
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regards Andrew T. |
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