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Old 16th October 2002, 04:35 PM   #1
cowanrg is offline cowanrg  United States
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Default what value would this be?

according to my attached picture, what would be the resistance across the positive and negative leads? (assuming im trying to make a dummy load for bench testing my amp). the resistors are 50W, 36ohm dale resistors. im really bad with kirchkoff's law, its been like 6 years.
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Old 16th October 2002, 05:26 PM   #2
HDTVman is offline HDTVman  United States
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21.333 ohms

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Bruce
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Old 16th October 2002, 05:37 PM   #3
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In the text you mention 36 ohm, and in the diagram you say 32. Assuming 32 is the correct number, the total is 21.3 ohms as Bruce said. If 36 is the correct number, the total is 24 ohms.

If 32 is the correct value, 4 in parallel will give you 8 ohms, 8 will give you 4 ohms.
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Old 16th October 2002, 06:02 PM   #4
cowanrg is offline cowanrg  United States
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oh, they are 36. so i guess its not possible to get an 8 ohm load from that then... sux.
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Old 16th October 2002, 06:13 PM   #5
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5 of them in parallel will give you 7.2 ohms. Close enough to 8, maybe?
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Old 17th October 2002, 05:45 AM   #6
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Default how many do you have?

Nine(!) in parallel would be 4 ohms.
Do that twice, and put the 2 groups in series for 8 ohms.
This is assuming you've got an unending supply of the things!
Still, at least power dissipation per resistor won't be a problem...

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