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16th October 2002, 04:35 PM  #1 
diyAudio Member

what value would this be?
according to my attached picture, what would be the resistance across the positive and negative leads? (assuming im trying to make a dummy load for bench testing my amp). the resistors are 50W, 36ohm dale resistors. im really bad with kirchkoff's law, its been like 6 years.

16th October 2002, 05:26 PM  #2 
diyAudio Member
Join Date: Aug 2001
Location: Chicago area

21.333 ohms
Later Bruce
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16th October 2002, 05:37 PM  #3 
diyAudio Member
Join Date: Sep 2002
Location: Ontario, Canada

In the text you mention 36 ohm, and in the diagram you say 32. Assuming 32 is the correct number, the total is 21.3 ohms as Bruce said. If 36 is the correct number, the total is 24 ohms.
If 32 is the correct value, 4 in parallel will give you 8 ohms, 8 will give you 4 ohms. 
16th October 2002, 06:02 PM  #4 
diyAudio Member

oh, they are 36. so i guess its not possible to get an 8 ohm load from that then... sux.

16th October 2002, 06:13 PM  #5 
diyAudio Member
Join Date: Sep 2002
Location: Ontario, Canada

5 of them in parallel will give you 7.2 ohms. Close enough to 8, maybe?

17th October 2002, 05:45 AM  #6 
diyAudio Member
Join Date: Sep 2002
Location: Hudson Valley, New York

how many do you have?
Nine(!) in parallel would be 4 ohms.
Do that twice, and put the 2 groups in series for 8 ohms. This is assuming you've got an unending supply of the things! Still, at least power dissipation per resistor won't be a problem... Cheers, BC 
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