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Old 27th March 2005, 12:27 PM   #1
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Default how do you convert 9V to 3.6V

how do you convert 9V to 3.6V using resistors and will it work? Any help appreciated. In ther words, how do I do the sums?
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Old 27th March 2005, 12:48 PM   #2
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Whatz the required load curent...Whether regulation necessary..
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Old 27th March 2005, 01:56 PM   #3
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Default how do you conver 9V to 3.6V

it's to run 3.6V LED from a 9V battery
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Old 27th March 2005, 01:57 PM   #4
paulb is offline paulb  Canada
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http://www.allaboutcircuits.com/vol_1/chpt_6/1.html
Note that your load (whatever you need the 3.6V for) is one of the divider resistors. You need to know its resistance, or how much current it draws at 3.6V (R=V/I). If the load changes (draws more or less current), its voltage will also change. Using resistors only to drop voltage has no voltage regulation characteristic.
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Old 27th March 2005, 02:08 PM   #5
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Many options:
Constant current source or Exotic LED drivers (white) from National.com or ti.com texas inst
Or simple current limitting resistor>>>>9-3.6/ LED current in milliamp = resistance in Kohms.
For 10ma LED Current R=540 OHMS (560 OHMS nearest commercial value)
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Old 27th March 2005, 05:44 PM   #6
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If all you are doing is lighting a few LEDs then use a simple series resistor to derive the correct current. The total voltage across the arrangement is totally unimportant, its the current that counts.

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Old 27th March 2005, 05:51 PM   #7
lgreen is offline lgreen  United States
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Default LED Equation

The LED equation is here.

Just use 1 resistor in series, use the formula.

For a typical amber LED Vf is about 2V, and If is about 20mA. So for 9V I get 350 ohms. To be safe, I'd use 500 or 1K. They get pretty bright even without using them to their max specs.
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