I need information about STK4050V

Dj BASS AMP · 4th July 2002, 01:31 PM

hi all!

I need information and circuit of STK4050V

Thanks!!!...

e96mlo · 4th July 2002, 02:20 PM

This site

http://www.datadart.com/al/sanyo/sanyodata.htm

contains the data sheet. It's also a good idea to check the data sheet for STK4048XI as it is contains a bit more information and as they are quite similar.

/Marcus

Dj BASS AMP · 4th July 2002, 02:35 PM

thanks!

but in the site not have a circuit of STK4050V

e96mlo · 4th July 2002, 02:37 PM

Did you even bother to look in the data sheet?

/Marcus

Freddie · 4th July 2002, 02:38 PM

Quote:

but in the site not have a circuit of STK4050V

STK4050 is there.. You didn't look very carefully did you?

http://www.datadart.com/al/sanyo/STK4050V.pdf

Dj BASS AMP · 4th July 2002, 03:00 PM

THANKS!!!

and HOW MACH AMPER THE STK4050V IS NEED?

i now is need 66V but i dont now how mach amper (A) is need??

e96mlo · 4th July 2002, 03:13 PM

Ohms law:

U = R*I => I = 66 V/8 Ohm = 8,25 A

16,5 A is needed for a 4 Ohm load. But these are peak currents so 8,25 A/(sqrt(2)) = 5,8 A continous and the double for 4 Ohms.

And add some to count for the losses...

/Marcus

Dj BASS AMP · 4th July 2002, 03:35 PM

THANKS U!!!

I build a amp With 2 STK4050V IN 8 Ohm

soo i need a power 66V ~ 16.5A in a 8 Ohm (for two STK)

or 66V ~ 30A in a 4 Ohm ( for two STK)...

yes??

Dj BASS AMP · 4th July 2002, 03:47 PM

if .............

66V ~ 8Ohm (IN STK4050V) = 200W R.M.S

soo....

66V ~ 4Ohm (in stk4050V) = W ????

e96mlo · 4th July 2002, 03:53 PM

U=R*I
P=U*I

With these formulas you can do most of the calculations you need. But remember that Up-p = (sqrt(2))*Urms and the same for current.

This means that the power doubles when you take half the load.

The transformer you need will be quite large (>1000 VA).

/Marcus

4th July 2002, 01:31 PM	#1
Dj BASS AMP Account Disabled Join Date: Jul 2002	I need information about STK4050V hi all! I need information and circuit of STK4050V Thanks!!!...

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4th July 2002, 02:20 PM	#2
e96mlo diyAudio Member Join Date: Apr 2002 Location: Helsingborg, Sweden	This site http://www.datadart.com/al/sanyo/sanyodata.htm contains the data sheet. It's also a good idea to check the data sheet for STK4048XI as it is contains a bit more information and as they are quite similar. /Marcus

4th July 2002, 02:35 PM	#3
Dj BASS AMP Account Disabled Join Date: Jul 2002	thanks! but in the site not have a circuit of STK4050V

4th July 2002, 02:37 PM	#4
e96mlo diyAudio Member Join Date: Apr 2002 Location: Helsingborg, Sweden	Did you even bother to look in the data sheet? /Marcus

4th July 2002, 03:00 PM	#6
Dj BASS AMP Account Disabled Join Date: Jul 2002	THANKS!!! and HOW MACH AMPER THE STK4050V IS NEED? i now is need 66V but i dont now how mach amper (A) is need??

4th July 2002, 03:13 PM	#7
e96mlo diyAudio Member Join Date: Apr 2002 Location: Helsingborg, Sweden	Ohms law: U = R*I => I = 66 V/8 Ohm = 8,25 A 16,5 A is needed for a 4 Ohm load. But these are peak currents so 8,25 A/(sqrt(2)) = 5,8 A continous and the double for 4 Ohms. And add some to count for the losses... /Marcus

4th July 2002, 03:35 PM	#8
Dj BASS AMP Account Disabled Join Date: Jul 2002	THANKS U!!! I build a amp With 2 STK4050V IN 8 Ohm soo i need a power 66V ~ 16.5A in a 8 Ohm (for two STK) or 66V ~ 30A in a 4 Ohm ( for two STK)... yes??

4th July 2002, 03:47 PM	#9
Dj BASS AMP Account Disabled Join Date: Jul 2002	if ............. 66V ~ 8Ohm (IN STK4050V) = 200W R.M.S soo.... 66V ~ 4Ohm (in stk4050V) = W ????

4th July 2002, 03:53 PM	#10
e96mlo diyAudio Member Join Date: Apr 2002 Location: Helsingborg, Sweden	U=RI P=UI With these formulas you can do most of the calculations you need. But remember that Up-p = (sqrt(2))*Urms and the same for current. This means that the power doubles when you take half the load. The transformer you need will be quite large (>1000 VA). /Marcus

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