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#1 |
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Did it Himself
diyAudio Member
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I'm designing a PSU using LM317T/LM337T regs. The National Semiconductor datasheet states that the output voltage is calculated by:
Vout = 1.25 * (1 + (R2 / R1)) + (Iadj * R2) where Iadj = 1.25 / R1 However, using this formula on the Typical Applications circuits, I cannot get anything like what voltage they say I should be getting. ![]() This is further complicated by the LM337L datasheet stating that the output voltage is calculated by: Vout = 1.25 * (1 + (R2 / R1)) Which gives apparantely correct results. ![]() Only this datasheet has the formula in this way, the LM317L, LM317T and LM337T all have the formula as in the first case. The L suffix is TO92 package and the T suffix is TO220 package.Has anybody actually got any proven formula or values I can try? I built one using L suffix parts and according to the second formula and it worked fine, but I want to use T suffix parts now.
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#2 |
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diyAudio Member
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I(adj) is the current on the "adjust" pin, not the total current pulled through the device -- it's measured in microamps -- Nat Semi has min/max/avg values on the datasheet. -- something like 50uA
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#3 |
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diyAudio Member
Join Date: Nov 2002
Location: Netherlands
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Hi Richi,
I_adj is indeed the current flowing out of the adjust pin. If you keep the recommended value for R2, 220 - 240 ohms, you can safely ignore I_adj and use the formula for the LM317L as well for the LM317T. Cheers
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#4 |
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Electrons are yellow and more is better!
diyAudio Member
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Here is a spreadsheet which I made for the purpose.
Use it
__________________
/Per-Anders (my first name) or P-A as my friends call me Tube Buffered Gainclone in work |Thread |
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#5 |
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Did it Himself
diyAudio Member
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#6 |
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Electrons are yellow and more is better!
diyAudio Member
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Good that you found out. In real life you can have R1 up to 1 kohms without problems. Iadj which cleary is stated
is far less than worst case.
__________________
/Per-Anders (my first name) or P-A as my friends call me Tube Buffered Gainclone in work |Thread |
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