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#1 |
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Did it Himself
diyAudio Member
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I'm designing a PSU using LM317T/LM337T regs. The National Semiconductor datasheet states that the output voltage is calculated by:
Vout = 1.25 * (1 + (R2 / R1)) + (Iadj * R2) where Iadj = 1.25 / R1 However, using this formula on the Typical Applications circuits, I cannot get anything like what voltage they say I should be getting. This is further complicated by the LM337L datasheet stating that the output voltage is calculated by: Vout = 1.25 * (1 + (R2 / R1)) Which gives apparantely correct results. Only this datasheet has the formula in this way, the LM317L, LM317T and LM337T all have the formula as in the first case. Has anybody actually got any proven formula or values I can try? I built one using L suffix parts and according to the second formula and it worked fine, but I want to use T suffix parts now.
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#2 |
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diyAudio Member
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I(adj) is the current on the "adjust" pin, not the total current pulled through the device -- it's measured in microamps -- Nat Semi has min/max/avg values on the datasheet. -- something like 50uA
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#3 |
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diyAudio Member
Join Date: Nov 2002
Location: Netherlands
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Hi Richi,
I_adj is indeed the current flowing out of the adjust pin. If you keep the recommended value for R2, 220 - 240 ohms, you can safely ignore I_adj and use the formula for the LM317L as well for the LM317T. Cheers |
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#5 |
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Did it Himself
diyAudio Member
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#6 |
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Electrons are yellow and more is better!
diyAudio Member
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Good that you found out. In real life you can have R1 up to 1 kohms without problems. Iadj which cleary is stated
is far less than worst case.
__________________
/Per-Anders (my first name) or P-A as my friends call me |
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