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#1 |
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diyAudio Member
Join Date: Sep 2012
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What kind of resistors would I need? And what would their values be?
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#2 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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You need to know the current for the required 1 volt voltage drop. V=I*R. So your Resistor = 1 volt/your current...
Why are you dropping one volt?
__________________
All right, but apart from the sanitation, medicine, education, wine, public order, irrigation, roads, the fresh water system and public health, what have the Romans ever done for us? Life of Brian |
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#3 |
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diyAudio Member
Join Date: Sep 2012
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the device can put out around 2 amps exactly on the mark and no higher.
I need to drop it one volt to run my laptop because the original laptop is gone and I don't want to buy a new charger for it. the charger I have runs fine and I wish to use it to run my newer laptop. but the laptop requires 18 volts DC and 1.5 amps and since I don't have a charger for it I wish to use the one I already have. if I can use some simple resistors to drop it by one volt that would be great. |
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#4 |
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diyAudio Member
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Find a large 3A diode,and wire in in series with the positive lead. It will drop ~0.7V. That should be close enough. (~18.3V)
My last laptop was rated for 16V,but it would run on anything in the 14-18V range. Edit:typo Last edited by DigitalJunkie; 18th February 2013 at 12:31 AM. |
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#5 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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I actually would not bother for 1 volt. the laptop should be able it take it with no issues...it will only take the amps it needs...
__________________
All right, but apart from the sanitation, medicine, education, wine, public order, irrigation, roads, the fresh water system and public health, what have the Romans ever done for us? Life of Brian |
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#6 |
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diyAudio Member
Join Date: Sep 2012
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I tried it before but the laptop doesn't turn on. I see the lights flicker madly when its plugged in. not a good thing. it scares me. so I want to try dropping the voltage by one volt to see if it makes a difference.
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#7 |
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diyAudio Member
Join Date: Jul 2003
Location: Dona paula, Goa
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Use two doides in series. The theoretical forward drop of a diode is 0.6 volts but it can be anywhere from 0.4 to 0.7 volts.
Gajanan Phadte |
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#8 |
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diyAudio Member
Join Date: Nov 2005
Location: San Antonio
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Are you sure the laptop and supply are compatible?
I never really looked into it much, but I assumed the supplies were 3-conductor, with the 3rd being part of the charge management.
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It is error only, and not truth, that shrinks from enquiry. - Thomas Paine |
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#9 |
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diyAudio Member
Join Date: Dec 2010
Location: wigan
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What happened to the original charger for your newer laptop??????
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#10 |
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diyAudio Member
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sofaspud is right, many have 3 conductors so they will not work without the correct brands powersupply. The plug has a central spike and the plus and minus are the inner and outer of the barrel. Dell are infamous for this - the actual charger could be standard but for the lockout from the data line.
dell-laptops-reject-third-party-batteries-and-ac-adapterschargers-hardware-vendor-lock-in/ If this is not one of the trapped brands then a couple of 5Amp diodes in line will drop 1-1.2 v or so. |
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