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#11 |
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diyAudio Member
Join Date: May 2007
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You said "the output resistance will be 1/hoe + Re*hfe, but the latter term usually dominates". This means that hfe directly appears as a multiplying factor, however large it is. It does not assymptotically disappear.
I have just had a look at Sedra and Smith. For the output impedance of a common base stage they give r0(1 + gm R'E) where r0 is the bare collector impedance (from the Early effect), gm is gm, and R'E is the parallel combination of RE (emitter resistor) and Rpi (base resistance). This is for high hfe. I guess Rpi increases with hfe, so can be ignored in the high hfe limit. So essentially we get r0(1+gmRE) = r0 + gmR0RE = r0 + mu RE (= ra + mu Rk in valve speak). So two different three-terminal devices (valve and BJT) essentially work in the same way, as they must - different approximations may be valid though. Let's backtrack. r0 does not depend on hfe, but on Early voltage. gm does not depend on hfe, but on the junction temperature and current. Rpi is the only thing which depends on hfe, as Rpi = hfe/gm (I think that is right). So we have r0(1 + gm RE hfe/(gm(RE+hfe/gm))) = r0(1 + gm RE hfe/(gm RE + hfe)) which I suppose could be written as r0(1 + (gm RE)||hfe) [where x||y means xy/(x+y)]. So high hfe increases output impedance up to the point where hfe exceeds gm RE; beyond that diminishing returns set in. If we assume one diode drop across the emitter resistor then gm RE will be around thirty so we want hfe to be greater than thirty to optimise the circuit. I'm still not clear I really understand it, but I think I understand it better than I did an hour ago! |
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#12 |
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diyAudio Member
Join Date: Dec 2005
Location: Kuala Lumpur
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#13 |
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diyAudio Member
Join Date: May 2007
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OK, so hfe and Early voltage have (to some extent) a common source. Which way round does it work? Will higher hfe samples also tend to have higher or lower intrinsic collector resistance?
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#14 | |
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diyAudio Member
Join Date: Sep 2006
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Quote:
Here is the comparison with BC847's. The quasi-static output impedance is plotted for the three hfe classes, and in addition, two synthetic classes have been added: Class mB is a A with just the Hfe brought to the B level and all other parameters unchanged, class mC is the same for the C. The 847A has ~4.7 megohm output impedance, the class mB ~5.1 megohm and class mC 5.3 megohm: no surprise there. But when "actual" transistors are measured, the difference is reversed, and quite dramatically: now the impedances are 2.9 and 1.9 megohm respectively: Conclusion: the lower Hfe types are normally better for this kind of application
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#15 |
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diyAudio Member
Join Date: May 2007
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Interesting. So for this type of CCS we may want hfe to be somewhat greater than 30, but not much more. Maybe somewhere around 100 would be optimal?
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#16 |
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diyAudio Member
Join Date: Sep 2006
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In theory, maybe. Problem, to find such a low Hfe in general purpose transistors, your only choice is high voltage types, with specific processes and as a result generally ugly other characteristics like high internal parasitic resistances which will ruin the benefit of the low Hfe.
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#17 |
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diyAudio Member
Join Date: Feb 2003
Location: ..
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transistors are cheap today - why obsess over "the best one" when two cheap Q can give order of magnitude better performance than "the best one"
cascode with base current reinjection http://www.essex.ac.uk/csee/research...%20cascode.pdf or the "Baxandall Super Pair" - which we should properly credit to Boxall (try forum Google Search) these do increase the order of the response - introduce the possibility of RF oscillation - which can be tamed with little compromise to their audio frequency performance Last edited by jcx; 9th October 2012 at 05:34 PM. |
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#18 |
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diyAudio Member
Join Date: May 2007
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OK, let's put it another way: provided that hfe is sufficiently high (which means >> 30 for the simple CCS) and other things are not compromised, then the lower the hfe the better because that is correlated with high collector resistance. The minimum hfe would increase of the base voltage is raised and so a larger emitter resistor is used.
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#19 |
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diyAudio Moderator
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Yes, but a high hfe and (relatively) high emitter resistance totally overwhelm even the highest collector resistances (1/hoe, basically).
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If there's a sucker born every minute, where do the rest of them come from? |
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#20 |
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diyAudio Member
Join Date: May 2007
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Since the term involving hfe multiplies collector resistance, rather than adding to it, hfe cannot overwhelm collector resistance.
High emitter resistance helps, provided it arises from high base voltage and not low current, as we also want high gm. |
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