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#11 |
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diyAudio Member
Join Date: Jul 2008
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I am making a device which is not related to audio and not related to PSUs.
I am making this device for my own personal use. I am not 100% certain about the device description yet, but I have a rough idea. I will need to experiment to get more information. I have worked "backwards" and I decided I needed to use a transformer. Obviously this may not be the right thing to do - but it is a start. A general description is this: The device must produce an output of 200KHz sinusoidal at a peak of 50 Volts. The output of the device will be applied onto a unit which may have a resistance of about 400-800 ohms (this is not verified yet). The unit measures approximately 15 cm - 20 cm and an electric field of 1V-2V / cm must be created. The electrodes of the device will be attached to the unit via two pads which will also present their own resistance, may be 100Ohms on each pad (this is not verified yet as the pad material has not been chosen yet). So far I have created one module: a 200KHz sinusoidal generator producing 4.2V peak into a load of 5 Ohms. The explanation is: The generator is a Wein bridge using an dual audio op-amp LM-4562 where the first op-amp generates the 200KHz and the second op-amp amplifies/buffers it to get a final 4.2V peak (2.97V RMS). There is also a transistor push-pull stage to allow us to drive 2-5 Ohms. Now all that remains is to transform the 4.2V peak into 50V peak. For that I would need a transformer with turns ratio of approx 12. That means that the load on the secondary, a worst case hypothetical 400 ohms (not verified yet) will be reflected back to the primary as 400 / 12^2 = 2.82 Ohm. So my first stage has to be able to drive a 2.82Ohm load at 200KHz and at 4.2 V peak. Now comes the selection of the transformer. The transformer is needed because the device is powered by 2 6V batteries - therefore creating a +/- 6 V supply. So far I know that the transformer needs to have a turns ratio of 12, work at 200KHz sinusoidal and drive a load of 400 Ohms at the secondary. I am not sure about the power of this transformer, but I tell you I tried my device on a 5 Ohm resistor (to simulate driving the transformer) and both the resistor and the output transistors get very hot (must use bigger heatsinks). If you can tell me what transformer I need and so on you'd save me a lot of reading
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#12 |
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diyAudio Member
Join Date: Jul 2008
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here's what I have made so far
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#13 | |
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diyAudio Member
Join Date: Jul 2008
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Quote:
Yesterday I found a few RM10 cores and bobbins in my drawer , I wound 10-11 turns enamel for the primary and 100+ turns for the secondary (got bored and stopped counting after a while). I then put the whole thing together and held the two halves with electrician's tape. By testing Vp and Vs on no load, it seems I have wound a ratio of 1:10 rather than the 1:12 as I should have (next time I will count). I have also checked and the transformer is not getting hot (or even warm) but I have ordered digital thermometers to make sure. Is there an *easy* way to combine (a) frequency (b) power (c) with/without DC component to be able to arrive at the size of the core needed, eg RM8, RM10, RM12 etc? "Have you calculated what inductance you will need on the transformer windings?" No, I have no idea how to do that. Is there an easy way to calculate it ? Last edited by akis; 24th April 2012 at 11:35 AM. Reason: added comments |
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#14 |
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diyAudio Member
Join Date: Dec 2003
Location: Nottingham UK
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Find the 'Ferroxcube' app note called "soft Ferrites and Accessories" on the web. I think the latest version is the 2009 one. In this you will find a set of graphs for the different type of cores showing the gap size required for a given I^2 x L for the different sizes of that core. So if you knew that your peak I might be 1A (as you have no dc flowing) and your required inductance was 2mH (say), then your I^2 x L would be 2mJ. Simply look up on the graphs what core size is appropriate.
The required primary inductance is the same as for any other transformer. Make it high enough that your magnetising current at the operating frequency is very low compared with the current actually providing the real ouput power. |
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#15 |
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diyAudio Member
Join Date: Nov 2011
Location: UK
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You need to identify what core material you have.
This is often stamped onto the core and will be something like N87. |
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#16 |
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diyAudio Member
Join Date: Jul 2008
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Hi. I have been reading but still have tons of questions.
I have used an RM10 with AL = 4500nH, me=1650, gap=0, length = 44.6 mm and area = 96.6 mm^2. I have wound 10 turns of 18 AWG wire on the primary and 100 turns of 30 AWG (or even thinner) on the secondary. I have used it under these conditions and it seems "OK". F = 200KHz pure sinusoidal primary : 2.5 V RMS secondary : 25 V RMS @ 50 mA RMS However given what I have read so far, I *think* I should have started by doing core power calculations and then the number of primary turns and so on. So what I need is a tool to input the requirements and get the necessary info on cores to use ( effective area and length, permeability, flux (the AL value whatever that is), the wires to use and the number of turns |
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#17 |
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diyAudio Member
Join Date: Nov 2011
Location: UK
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If its not overheating then you are below the magnetic saturation of the core which is good.
Good design normally keeps the core flux below 1000mT (320mT is used by the military for reliability) Irrelevant of the core, the windings must be capable of the currents involved. Last edited by KatieandDad; 24th April 2012 at 08:04 PM. |
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#18 |
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diyAudio Member
Join Date: Dec 2003
Location: Nottingham UK
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The AL value for a core is specified in nH per turn^2.
If a core has an AL value of 200nH, then 1 full turn of wire on the core will give an inductance of 200nH. Two turns will give 800nH, three turns 1.8uH etc: |
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#19 |
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diyAudio Member
Join Date: Jul 2008
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Hi again. What you say makes sense. I know I have 10 turns on the primary and 100 turns on the secondary, so according to AL=4500nH I should be reading 0.45uH for the primary and 45uH for the secondary - which is very close what I have just measured it to be.
How do I find out what the saturation flux for the transformer is? Last edited by akis; 25th April 2012 at 07:37 AM. |
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#20 |
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diyAudio Member
Join Date: Dec 2003
Location: Nottingham UK
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I guess you mean 0.45mH on the primary and 45mH on the sec?
This seems to be in the right region for the transformer operating at 200kHz. |
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