|
|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
| Parts Where to get, and how to make the best bits. PCB's, caps, transformers, etc. |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
Join Date: Jun 2010
|
Hello all, this is my first post at diyAudio.
I've known the forum for a long time, but never joined until now. I'm sure I will learn a lot of things here. I'm just curious, and would like to know if it's possible to use the Burson attenuator on regular amplifiers. The attenuator only come with 3-pins (L, R, G), and according to Burson, it's specifically designed that way for installation with their amplifiers. ![]() Here is a picture of the attenuator installed in their headphone amplifier, the HA-160: ![]() It's not really evident in that photo, but the line goes from the RCA inputs to a 3-pins connector on the PCB marked INPUT. From the PCB there is a 3-pin connector marked VOLUME that goes to the 3-pins on the attenuator. My friend suggested that the resistors on the right side of the attenuator may be run in series with the attenuator, and that the attenuator is basically a variable resistor. But I still don't get how the thing works to attenuate the signal. |
|
|
|
|
#2 |
|
diyAudio Member
|
If it is a var resistor it works by connecting a resistor after the series resistor to gnd. That attenuates the signal, right?
So when you switch different resistors to gnd you can control volume. The downside is that the resistance seen by the source varies with volume, and at min volume it is only the series resistor. So the source must be able to drive that series resistor value as load. jd
__________________
/Another new issue: Linear Audio Volume 3! |
|
|
|
|
#3 |
|
diyAudio Member
Join Date: Jun 2010
|
Hi Janneman,
Yes, I get what you mean. But still I'm not very clear on how to implement this on a circuit that's designed to be used with regular 6-pin attenuators? |
|
|
|
|
#4 |
|
diyAudio Member
Join Date: Jun 2010
|
I'm wondering if this would be correct:
Line in --> R1 (some large resistance, 50K-100KOhms) --> --> Amplifier Input --> Attenuator |
|
|
|
|
#5 | |
|
diyAudio Member
|
Quote:
), and a 'hot' pin for each of the channels. What you do is use a series R from input jack to amp input. Then you connect a 'hot' pin to the series R at the side of the amp input, for each channel, and the gnd pin to, ehhh, gnd.You can try it out, you can't break anything. One issue is the value of the series R; that should be in the Burson specs. If you can't find it, start with 10k. If the level is too low, you can decrease it down to a couple of k. Again, you can't break anything so just do some R&D ![]() jd
__________________
/Another new issue: Linear Audio Volume 3! |
|
|
|
|
|
#6 |
|
diyAudio Member
Join Date: Jun 2010
|
Thanks. I managed to get it to work, exactly by adding a serial resistor. I happened to have 10K ohms laying around, so I used that and it works great.
|
|
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
|
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Gainclone and Burson opamp? | Doug DuBose | Chip Amps | 1 | 27th March 2009 01:52 AM |
| Burson Dual opamp HELP | chofaichan | Digital Source | 19 | 29th March 2008 04:36 AM |
| Burson Buffer | mark_titano | Digital Source | 4 | 21st November 2006 01:06 AM |
| New To Site? | Need Help? |
| Page generated in 0.09634 seconds (77.43% PHP - 22.57% MySQL) with 10 queries |