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#1 |
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diyAudio Member
Join Date: Dec 2008
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Hi all, I have trouble obtaining the original transistors of the attached amplifier. So I want to use equivalent transistors. please tell me which transistors are better for using in the amplifier.
(The original amplifier uses +/-95V rails but I'm going to use it with +/-50V) For: MJE15034) TIP41 or 2SC669 ? MJE15035) TIP42 or 2SB649 ? IRF510) IRF540 or IRF 630 or IRF640 or IRF730 or IRF740 or IRF840 ? Best regards Ermac |
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#2 |
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diyAudio Member
Join Date: Mar 2007
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You'll be better off with a new design. Using integrated circuits will make design much easier.
__________________
"Fully on MOSFET = closed switch, Fully off MOSFET = open switch, Half on MOSFET = poor imitation of Tiffany Yep." - also applies to IGBTs! |
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#3 |
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diyAudio Member
Join Date: Sep 2004
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Hi,
All transistors are easily obtainable through regular sources, Digikey, etc. It's a decent design, but do heatsink adequately. Cheers! |
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#4 |
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diyAudio Member
Join Date: Dec 2008
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I do know all these parts are common and easy to find... but I can't buy them in my country.
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#5 | |
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diyAudio Member
Join Date: Sep 2004
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Quote:
What places are available to you? Cheers! |
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#6 | |
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diyAudio Member
Join Date: Dec 2008
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Quote:
I'll use TIP41/42 instead of MJE15034/35. I named a few IRFxxx; can they be used instead of the IRF510 in this amplifier? |
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#7 | |
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diyAudio Member
Join Date: Sep 2004
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Quote:
Cheers! |
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#8 |
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diyAudio Member
Join Date: Dec 2008
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OK, thank you !
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#9 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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the irf510 is used as a Vbe multiplier.
In this location a BJT can be used. A To92 can be glued or clamped to the heatsink. or inserted into a close fitting hole drilled in the heatsink or a To126 device can be used bolted to the heatsink or bolted on top of one of the output devices. The Vbe multiplier transistor must monitor the temperature of the output devices as closely as possible. Change the 10k VR to 2k and add a resistor in series with it. Try 160r If your VR is accidentally set to 0r0 then the maximum voltage from the Vbe multiplier will be ~{2200/160 + 1} * Vbe ~=8.8V The minimum voltage will be ~{2200/(160+2000) + 1} * Vbe ~=1.2V this will ensure the FETs turn off at minimum Vbe voltage and turn on at maximum Vbe voltage. But, I repeat my warning mirrored by others. You are in for a mighty fright that will be expensive and potentially very dangerous when this amplifier blows up. Start with something much simpler and much cheaper and of much lower voltage.
__________________
regards Andrew T. |
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#10 | |
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diyAudio Member
Join Date: Dec 2008
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Quote:
Would you please tell us why other MOSFETs (eg IRF740) cannot be used? Kind regards, Ermac |
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