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#1 |
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diyAudio Member
Join Date: Feb 2003
Location: Bayreuth
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Hi everybody!
What I want to do ist to reduce the current ripple in my 65V-0V-65V (5A-0-5A) PSU. It is based on: 2x block transformer (230V/46V 320VA) 8x 4700myF/100V electrolytic filter capacitors 2x 700V/35A metall bridge rectifier 4x 10myF MKP capacitors (2 per rail) and 2 4k7/10W resistors I use it to power my 2x150W A/B power amplifier. My question is: Can I reduce the ripple current by wireing the second transformer antiphase so that the maximum + of the one trafo is at the same time than the max - of the other trafo? I thought, that this would smooth the ripple at the end of the PSU and give a cleaner voltage for the amp. Is this right? Please give me your suggestions! Thanks, the toasted |
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#2 |
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diyAudio Member
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Quite simply, it is impossible, without having the DC cancel as well (i.e. two +65V supplies). Note that would be measuring +65 to +65, not +65 to ground, which would still have the same hum. (Point being, they both have the same hum.)
What is an MKP cap? Anything special? Reference to purpose? In any case, to remove hum completely (practically so anyway), throw in a choke. 150W isn't small beans, so the chokes (one for each, + and -) will need to be pretty large. BTW, hold down ALT then on the keypad, type 0181, then release ALT. You get a Greek mu 'µ'. If that's too much bother, at least use a plain 'u' for micro. Note also that, though many will misunderstand it (go figure), the correct letter for such large values is 'm', thousandths. Thus, 10,000µF = 10mF = .01F. Tim |
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