Go Back   Home > Forums > Design & Build > Parts
Home Forums Rules Articles Store Gallery Blogs Register Donations FAQ Calendar Search Today's Posts Mark Forums Read

Parts Where to get, and how to make the best bits. PCB's, caps, transformers, etc.

Please consider donating to help us continue to serve you.

Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving
Reply
 
Thread Tools Search this Thread
Old 6th July 2007, 01:31 PM   #11
diyAudio Member
 
Join Date: Mar 2001
Location: Sydney
The impedance of the cap is determined by 1/(2*pi*f*c), where pi=3.141, f=50Hz and c=capacitance in farads (you need to divide the 0.33uf by 1000000). For 0.33uF, this produces an impedance of about 9.6k. Calculate the current drawn by the relay coil (24v coil divided by whatever the coil resistance is), then use ohms law to calculate the voltage drop across the cap. By changing the value of the cap it changes the impedance and hence changes the voltage drop for a given current.
  Reply With Quote
Old 6th July 2007, 01:39 PM   #12
jarthel is offline jarthel  Australia
diyAudio Member
 
Join Date: Jan 2002
Location: somewhere in Australia
Quote:
Originally posted by smithy666
The impedance of the cap is determined by 1/(2*pi*f*c), where pi=3.141, f=50Hz and c=capacitance in farads (you need to divide the 0.33uf by 1000000). For 0.33uF, this produces an impedance of about 9.6k. Calculate the current drawn by the relay coil (24v coil divided by whatever the coil resistance is), then use ohms law to calculate the voltage drop across the cap. By changing the value of the cap it changes the impedance and hence changes the voltage drop for a given current.

I assume the 9.6K value is then paralleled to the 2x 470K to get the final resistance equivalent?

why not just use resistance to drop the voltage?

thanks again
  Reply With Quote
Old 7th July 2007, 01:39 PM   #13
mzzj is offline mzzj  Finland
diyAudio Member
 
Join Date: Jul 2005
Location: 65N 25E
Quote:
Originally posted by jarthel



I assume the 9.6K value is then paralleled to the 2x 470K to get the final resistance equivalent?

why not just use resistance to drop the voltage?

thanks again
Using only resistor would result pretty high power dissipation for small circuit like that (around 5W for 230v operation)
  Reply With Quote

Reply


Hide this!Advertise here!

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools Search this Thread
Search this Thread:

Advanced Search

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off


Similar Threads
Thread Thread Starter Forum Replies Last Post
metal film or carbon film? Roushon Parts 36 17th October 2011 10:33 PM
Res Survey:....... Carbon film ...or... Metal Film ...............?? nina Chip Amps 13 14th April 2005 01:46 AM
Trouble with speaker protection circuit (Randy Slone's circuit) whalefat Solid State 3 13th April 2005 11:13 AM
Carbon film vs metal film resistors in a stepped attenuator? G Tubes / Valves 17 22nd August 2004 01:22 AM
Metal film resistors or carbon film in a tube amp? G Tubes / Valves 220 31st March 2003 02:57 PM


New To Site? Need Help?

All times are GMT. The time now is 03:37 AM.

Page generated in 0.07323 seconds (71.22% PHP - 28.78% MySQL) with 10 queries

Copyright ©1999-2012 diyAudio