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#1 |
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diyAudio Member
Join Date: Jan 2004
Location: Toronto, ON, Canada
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I realize that a current-source amp doesn't care about the impedance in that the magnitude of the current delivered is indepedent of the impedance; however, what about the phase? The current across an inductor lags behind the voltage, so from a conventional voltage-source amp the motion of the speaker would lag behind the voltage waveform going across its voice coil (I think).
Is it the same way with a current-source amp? |
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#2 | |
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diyAudio Member
Join Date: Feb 2004
Location: Stockholm
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Quote:
With the normal near-ideal voltage source the output is greatly affected by both. The voice coil inductance acts as a lowpass filter, typically of order 0.7 or so*, and the resistance keeps the response from peaking at fs (the resonant frequency of the driver). The resistance effect is highly desirable, but the inductance might not be. *Yes, filters are not only of integer orders. Since the voice coil inductance has an impedance that typically is proportional to f^(0.7) one could say that the filter order becomes 0.7. |
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#3 | |
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diyAudio Member
Join Date: Jan 2004
Location: Toronto, ON, Canada
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Quote:
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#4 | |
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diyAudio Member
Join Date: Feb 2004
Location: Stockholm
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Quote:
This has another positive effect; if the inductance is non-linear and causes distortion in the constant-voltage drive condition, it causes NO distortion in the constant-current drive condition. Funnily, the current source will produce a distorted voltage and this distortion compensates for the distortion caused by the non-linear inductance. |
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#5 |
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diyAudio Member
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Okay, that might be true for an ideal current source amp.
Not that I am any expert on this, (far from it), but I am given to understand that in real life current source amps the output will vary quite a bit with the impedance variation. This is in direct contrast with most solid state amps with near ideal voltage source behavior. Is this true?
__________________
"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#6 | |
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diyAudio Member
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Quote:
Since Vout = Iout * Rload, with current amps, Iout is fixed for a specific level, Rload changes therefore Vout varies all over the place. But the idea is that Vout doesn't matter with current drive, it's the current that matters. And that is a fixed ratio to input signal. So, yes, it's true, but who cares? Jan Didden
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/Another new issue: Linear Audio Volume 3! |
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#7 | |
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diyAudio Member
Join Date: Feb 2004
Location: Stockholm
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Quote:
You can make a very-near ideal current source. It will of course have the same limitations regarding maximum output voltage and current as the typical near-ideal voltage source (=most normal amplifiers). Here is a proof-of-concept design:
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#8 | |
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diyAudio Member
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Quote:
I do remember reading in Audio magazine an interview with a prominent designer, (I forget his name). He said that he thought in a few years, the cone loudspeaker would disappear from the high end of the audio market because in one octave, the signal comes at you as if it is ten feet in front of you, but in another octave the signal comes at you as if it was much farther back. I think that might be what he was referring to, but once again I am not entirely certain.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#9 | |
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diyAudio Member
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Jan and Svante:
I think I botched up the wording of the post you both replied to. When I said: Quote:
Am I correct on this?
__________________
"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#10 | |
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diyAudio Member
Join Date: Feb 2004
Location: Stockholm
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Quote:
The output towards higher frequencies will increase too, due to the voice coil inductance. |
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