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Old 16th November 2006, 01:42 AM   #1
boone is offline boone  
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Default Parallel cap to create 1.5 way?

A couple of times recently I've seen mention of useing a parallel cap ( like a zobel without the resistor ) to low pass one of the drivers in a 1.5 way configuration. Both times the drivers were hooked up in series. Is there something specific to a series hook up of the drivers that makes this work or would it work if the drivers were in parallel also? Or for that matter each driver being driven by a seperate amp channel ( my situation )?

Would the value of the cap be the same as would be used to high pass the driver at the same frequency?

Is the slope 6 db per octave? And does the slope steepen as the drivers impedence rises as opposed to a series inductor on an unzobeled driver where the rising impedence reduces the slope?

Thank you.

boone
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Old 16th November 2006, 12:23 PM   #2
sreten is offline sreten  
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Hi,

You need a series inductor to make a 1.5 way arrangement, the drivers in parallel.

You cannot make a 1.5 way syetem with the drivers in series.

/sreten.
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Old 16th November 2006, 12:58 PM   #3
Paul W is offline Paul W  
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The series cap configuration is useful for increasing LF power handling without adding baffle step compensation.

The speaker linked below used a series cap xo for the .5 woofers with line level baffle comp. The page explains how it works.

Value of the cap was determined for the specific purpose using LspCAD, so I didn't have any reason to see if was the same value as a highpass at the same frequency. The slope was ~6db per octave but don't remember if it varied with impedance (I'm thinking it didn't vary because the impedance of each driver is equal at any given frequency...no zobel was used).

Can't use it for parallel drivers. If you are using a separate amp for both drivers, you'll need to go with an inductor in series with the .5 driver...or go active.
Paul

MMTMM with cap
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Old 16th November 2006, 01:33 PM   #4
sreten is offline sreten  
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Hi,

OK. you can use the series capacitor configuration but you don't get BSC.

Each speaker driven by a seperate amplifier is equivalent to the parallel
configuration and a parallel capacitor cannot be used on one driver, a
series inductor would be used.
Though its a lot easier to but a passive filter on the amplifier input.
With seperate amplifiers you will get BSC.

/sreten.
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Old 16th November 2006, 01:45 PM   #5
boone is offline boone  
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Stren & Paul W,

Thank you for your replies.

I am not after bsc.

I'm wondering why when the drivers are hooked in series the cap "shunts" HF so the driver plays as a .5 ( low passing it in effect )
but the same driver by itself, shunted with a cap in the same way doesn't?

Thank you
boone
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Old 16th November 2006, 02:18 PM   #6
Paul W is offline Paul W  
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Boone,
SS amp acts as a constant voltage source...so the amp sees the cap as another load in parallel with driver. Amp is trying to drive a short at HF...not good!

Some resistance/reactance in series is needed to isolate cap from amp. Second driver in series provides isolation and allows cap to roll off HF.
Paul
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Old 16th November 2006, 02:33 PM   #7
boone is offline boone  
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Paul W,

How much series R is needed to do this ( min. )?

Thank you
boone
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Old 16th November 2006, 02:39 PM   #8
v-bro is offline v-bro  
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Just a couple of ohms (4 to 10 mostly), this is often done with ESLs because they tend to be a very heavy capacitive load too.
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Old 16th November 2006, 03:39 PM   #9
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Quote:
Originally posted by boone

How much series R is needed to do this ( min. )?
boone
Too much, ruins the Qt of the bass alignment, /sreten.
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Old 16th November 2006, 04:40 PM   #10
boone is offline boone  
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To all who have replied,

Thank you for your help.
I would like to rephrase one of my earlier questions. If I had a driver that I wanted to high pass at 200 hz - and at that freq. it's impedence was 6 ohms -and the various tables/calculators sugguested a 130uf cap in series to accomplish that, would that same 130uf cap paralleled with the driver create a kind of low pass at 200 hz?

Would 4 ohms of series R before the parallel cap affect the value of the cap?

v-bro
Is 4 ohms the absolute minimum to isolate the cap (less is better)

sreten
I think I have enough volume to accommodate a moderate increase in Qt

Thank you
boone
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