Suitable midrange cone, for bandpass mid in Unity horn. - Page 112 - diyAudio
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Old 19th September 2013, 09:55 PM   #1111
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Thomas, no luck with th aura drivers?
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Old 19th September 2013, 10:42 PM   #1112
Hrmmf is offline Hrmmf  Denmark
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Quote:
Originally Posted by Beau View Post
Thomas, no luck with th aura drivers?

Thomas-who?

/Thomas
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Old 20th September 2013, 02:28 AM   #1113
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B&C 5FCX44 5" Professional Coaxial Speaker 70 x 70 8 Ohm 294-5760

New B&C, not terribly expensive.

My thoughts would be to rip off that windscreen,
plug it with a simple wooden cone, and attempt
something of a paraline...
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Old 20th September 2013, 04:03 AM   #1114
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Thomas you, Hrmmf
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Old 20th September 2013, 06:13 AM   #1115
Hrmmf is offline Hrmmf  Denmark
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Quote:
Originally Posted by Beau View Post
Thomas you, Hrmmf
Aha!

Well, I actually prefer closed back, cloth surround, paper mids!

Is base my preferences on something JLH wrote about "ideal" midrange characteristics somewhere along this very active and ongoing Synergy thread.

Also, there must be a specific reason to why Danley prefers these types of mids his designs.

/Thomas
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Old 20th September 2013, 06:18 AM   #1116
tinitus is offline tinitus  Europe
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I will have to consider a 2" CD
rolled off top is ok for bass guitar
but the higher price is not

though the bigger CD might have other advantages

just now noticed a 1.4" BMS 4554 at 110EUR (and cheap shipping)
funny 1.4" CD, because the cone is the same used in 1" drivers (1.75"/44mm)
recommended 1khz xo point
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Old 20th September 2013, 07:22 AM   #1117
Hrmmf is offline Hrmmf  Denmark
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Originally Posted by JLH View Post
Every choice has a cause and effect. Also note that while I choose to simplify the script by using round ports, in real life I use slotted ports. I make the ports' width and length follow the Golden Ratio. So in case of that Visaton M10 script, the ports are approximately 1.55cm X 2.5cm and not really 2.2cm diameter
John, are kepping the width (1.55cm) as i fixed value, solving for x as the length variable:
1.55/x = 0.62 (ratio) -> x = 2.5 ?



Found it!

Golden Ratio

- Still, how do you decide on the width, by hunch ?

/Thomas
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Old 20th September 2013, 12:55 PM   #1118
tinitus is offline tinitus  Europe
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Originally Posted by Hrmmf View Post
Found it!

Golden Ratio

- Still, how do you decide on the width, by hunch ?
with the golden ratio ? ... estimating works fine
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Old 20th September 2013, 01:08 PM   #1119
Hrmmf is offline Hrmmf  Denmark
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Originally Posted by tinitus View Post
with the golden ratio ? ... estimating works fine
- Yes, the Golden ratio!

I mean you have to decide on an initial value, in this case I guess it's the width (1.55cm)

solving: x/1.55 = 1.618 -> x = 2.5

/Thomas
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Old 20th September 2013, 01:21 PM   #1120
tinitus is offline tinitus  Europe
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the important thing is that the hole is accurate area
and I suppose all should be equal size

if you also happen to believe in the blessings of golden ratio, that is good enough if estimated

golden ratio is known and proven to please the eye, and give balance in what you see
but I don't know if any other effects have ever been proven

but if designing asymmetric horn, I could still be tempted to use golden ratio between height and width
and should fit the golden ratio rule all the way from mid's pass holes to horn mouth exit
horn length might be a different matter, and depends on horn type
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