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MultiWay Conventional loudspeakers with crossovers 

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17th April 2006, 07:22 AM  #1 
diyAudio Member
Join Date: Nov 2004
Location: Melbourne

Crossover Summed Response
Hi All,
I am in the process of building some speakers, specifically in designing the crossover. I am having trouble assessing the summed response. All sources and websites I have visited so far have simply used the sum of the output voltages from each leg of the crossover  this doesn't seem right to me. Should it not be the sum of the power output from each leg of the crossover, with respect to the phase that it is output at? Assuming a resistive load (complex loads are much too complicated for this purpose), the power output will be proportional to the square of the voltage magnitude, at the voltage angle (assuming similar driver sensitivites and impedances/resistances): Output = Vwoofer^2 * exp(i.angle(Vwoofer)) + Vmid^2 * exp(i.angle(Vmid)) + Vtweeter^2 * exp(i.angle(Vtweeter)) I have used this formula, in conjunction with many different filter types (Bessel, Butterworth, Chebychev and others) to get a 3 way 3rd order crossover with the flattest frequency response (~ ±2dB variation). I must use at least a 2nd order crossover for the tweeter. I could not get a flat enough response with the second order crossover though. What are peoples thoughts? Thanks, regards, Chris. 
17th April 2006, 10:40 AM  #2 
diyAudio Member
Join Date: Mar 2006
Location: nsw

You are right in that it is more complex than that. You need four plots per driver to properly construct a crossover. It can be complicated but is drastically improved with a crossover simulator.
You need an impedance magnitude plot and that impedance's phase plot to calculate the effect of the crossover components on the driver. The filter transfer function translates to the effect on the driver's measured acoustic frequency response plot. The driver's acoustic phase plot is required to sum multiple drivers, and to see group delay issues. All of the above can be measured with simple equipment and will take an initial investment of time. 
17th April 2006, 02:34 PM  #3 
R.I.P.
Join Date: Nov 2003
Location: Brighton UK

Hi,
for what its worth Linkwitz/Riley croosovers are the only filters that theorectically sum to a flat power response, it is this that defines this filter type  which is only relevant to crossovers. I say theorectically because the response required is acoustic, not electrical, and the units also have to be time aligned. /sreten. 
17th April 2006, 04:56 PM  #4  
diyAudio Member
Join Date: May 2002
Location: Switzerland

Quote:
Quote:
Regards Charles 

17th April 2006, 06:03 PM  #5 
diyAudio Member
Join Date: Nov 2004
Location: Melbourne

lndm, I'm not sure I have the equipment or time to measure the acoustic phase plot of my drivers! However, I do have a signal generator and oscilloscope, and I have measured the impedance of the drivers, and will use zobels/resonant circuits to make it flat.
Sreten, I am currently looking into LinkwitzRiley circuits, thanks for that. Charles, which others sum flat? It should be the voltage^2 at voltage angles which sum flat, correct? Thanks for the help, Chris. PS, is there any problem using high (3rd to 4th) order crossovers in speakers apart from cost? I have been reading that their time/transient response is not that good. 
17th April 2006, 09:35 PM  #6 
diyAudio Member
Join Date: Mar 2004
Location: Melbourne, Australia

If you need some testing or simulations done Real, drop me line, I might be able to help you (I'm also in Melbourne).
David www.gattiweb.com 
18th April 2006, 01:02 AM  #7 
diyAudio Member
Join Date: Mar 2006
Location: nsw

You'd be surprised what you can do with a cro configured for lissajous (XY) patterns, a frequency table on paper, a little common sense, time and determination, for measuring phase.
These days I plug my mic into my soundcard and use FFT software to do it in seconds. Having spent many years designing crossovers by hand, I believe that no matter how much theory you absorb, or calcutations you make, you will virtually always need to tweak by hand/ear afterward, with an open mind. 
18th April 2006, 01:46 PM  #8  
diyAudio Member
Join Date: May 2002
Location: Switzerland

Quote:
H(s) = (1+sT+s^2*T^2+ ... + s^n*T^n)/(1+sT+s^2*T^2+ ... + s^n*T^n) Regards Charles 

18th April 2006, 04:02 PM  #9  
diyAudio Member
Join Date: Nov 2004
Location: Melbourne

David, thanks for the offer, I will pass my design by you, see what you think. It won't be for a few weeks though as I am currently overseas! In fact, I'll just post on the forum when I get back  I have done plots on MATLAB too of the summed responses.
lndm, I am not sure what you are talking about wrt the XY patterns, could you explain to me please? Quote:
H(s) = 1 in this case! Third order butterworth is what I have designed thus far  I am mainly checking to see that I have used the right formulas for getting the summed response  since no one has said otherwise, I assume that I am correct! Additionally, I mentioned that I did impedance measurements of the drivers, though this was in free space, no enclosure. Is this an issue? It only really affects the woofer (mid is dome type), which only needs compensation for the impedance rise at high frequencies  will this be different when in the enclosure? I will check it anyway when I have time to do all this stuff! Thanks all, Chris. 

18th April 2006, 09:04 PM  #10  
diyAudio Member
Join Date: Feb 2004
Location: Stockholm

Quote:
Hlp=1/(1+s/s0) Hhp=s/s0 / (1+s/s0) The sum of the two is (1+s/s0)/(1+s/s0)=1 

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