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#1 |
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diyAudio Member
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Ok, i've seen what a line-level BSC circuit can do (as per Rod Elliott - sound.westhost.com ), but i'm real curious.. Does a passive BSC do the same thing? i.e. attenuate sound above a certain frequency in a shelf manner.
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#2 |
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diyAudio Member
Join Date: Mar 2004
Location: Melbourne, Australia
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yes, absolutely.
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#3 |
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diyAudio Member
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http://zaphaudio.com/audio-speaker12.html
In this design, Mr Krutke says he has about 4.5dB of BSC on the woofer. But all he has in the woofer crossover is the inductor (1st order low-pass) and the LC notch filter (for the 8KHz breakup node). I'm getting a tad confused
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#4 |
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diyAudio Member
Join Date: Dec 2001
Location: Bremerton, WA.
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Khron,
The woofer driver is a complex impedance and judicious design with a minimal number of components can still yield the desired BSC curve. Take a look at the graph labeled "woofer filter effect." This shows the actual drive to the woofer and the shelving effect between 200-2000Hz that John was targeting. You'll see this kind of thing a lot with well-designed crossover networks......the actual topology might not look "generic" (or what you'd expect) but it still accomplishes the goal. Cheers, Davey. |
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#5 |
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diyAudio Member
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Thanks Davey, that does make sense
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