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#1 |
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diyAudio Member
Join Date: Jul 2005
Location: Bremerton, WA.
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Regarding series wiring (2) 4ohm speakers to get 8ohms
vs parallel wiring (2) 16ohm speakers to get 8ohms. When series wiring I get a 3db drop in SPL due to the increased resistance. When parallel wiring I get a 3bd increase in SPL, right? I'll use 2 drivers (PE's buyout section) for examples. A 10", 4ohm driver with an SPL of 93db. When wired in series the SPL of the pair would now be 90db. An 8", 16ohm driver with 83db SPL. When wired in parallel the SPL of this pair would now be 86db. Now since there would be 4 of each driver (2 per side), would there be any additional increase in SPL because of quantity. If I understand correctly, the (4) 10"'s would be back up to 93db while the (4) 8"s would stay at 86db or would they be 89db (86db + 3db more because of the additional pair? R/ Jim |
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#2 | |
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diyAudio Member
Join Date: Jun 2005
Location: The Netherlands
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Quote:
When wiring in series there will be a loss of 3 dB (double the resistance (-3), each driver gets half of the applied voltage (-3) but there's a doubling of drivers (+3)) compared to one driver. When you wire the 4 ohms drivers in series you'll get a SPL of 93-3 = 90 dB. As you mentioned, you're going to use four drivers. The SPL will increase with 3 dB (twice the number of drivers), so finally this turns out to 90+3= 93 dB. When you wire the 16 ohms drivers in parallel the SPL becomes 83+6 = 89 dB. Because of doubling the number of drivers, the SPL increases with another 3 dB, so you'll end up with 89+3 = 92 dB. regards Erwin |
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#3 |
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diyAudio Member
Join Date: Jul 2005
Location: Bremerton, WA.
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e-side,
Very good explination. Thank you very much. R/ Jim |
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#4 | |
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diyAudio Member
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Quote:
I believe the first paragraph is correct. When he takes two 4 ohm, 93 dB @ 2.83V/1M speakers and wires them in series, he will have the same sensitivity, 93dB @ 2.83V/1M. Since the single 4 ohms speaker draws 2 watts when fed 2.83 Volts, and the series pair draws 1 watt at 2.83 Volts, he will be cutting his power in half when he drives the series pair. However, the series pair has twice the cone area of a single driver, and that increases efficiency to compensate. Same goes for any voltage drive level. The series pair will be the same sensitivity as the single driver for any given voltage level, but will draw only half the power at that voltage level, whatever it is.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#5 | |
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diyAudio Member
Join Date: Jun 2005
Location: The Netherlands
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Quote:
So when you wire two resistors in series, and you apply 5 Volts to the circuit, each resistor gets 5/2 = 2,5 Volts. The same goes up for loudspeakers (I suppose). So when you wire two 4 Ohm drivers with a SPL of 93 dB in series, the following happens: 1) - Doubling of the resistance compared to one driver, so 3 dB less; 2) - Because of wiring two drivers in series the voltage applied to the circuit gets divided by the number of drivers, so each driver gets the half of the actual applied voltage to the circuit. This results in another decrease of sound level (I think 3 dB) 3) - Because twice the number of drivers is used, SPL increases with 3 dB ------------------------- 1) 93- 3 = 90 dB; 2) 90- 3(?) = 87 dB; 3) 87+ 3 = 90 dB = final SPL when those two 4 ohms drivers in series. I'm not exactly sure, but I think that point (2) should be taken into account, causing a different result. regards Erwin |
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#6 |
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diyAudio Chief Moderator
Join Date: Oct 2002
Location: Athens-Greece
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Kelticwizard got it right. This thing is documented in classic acoustics. Follow the Kelt.
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#7 |
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diyAudio Member
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Erwin:
Let's try this a different way. Let's compare a ten inch single unit speaker to a series unit speaker, as if the two speakers in series are one speaker. To do this, we use Bullock and White's Dos BoxModel, where the user inputs certain speaker parameters in the dark blue area illustrated below, and the aqua green area shows the calculated values. One of these calculated values is sensitivity per watt-not per 2.83 volts. Forget the box section for now-we are just dealing with the driver. Bullock and White's program, available here is very useful in this respect. Note: Ignore the TL program-they admit that it was an experiment which failed. But the Dos BoxModel for closed, vented, and PR is just fine. We take a typical 10 inch speaker with a sensitivity of 93 dB per watt, and fill in typical Thiele-Small values for it below:
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#8 |
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diyAudio Member
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Now, in order to combine two speakers into one, we change three things:
We double the Re - It goes from 3.0 ohms to 6.0 ohms. We double Sd, the Cone Area. It goes from 350 sq cm, (56 sq inches) to 700 sq cm, (112 sq inches). We double the Vas. Everyone knows you must double the box volume when you add another speaker to get the same response. So Vas goes from 80 L, (2.8 cu ft), to 160 L, (5.7 cu ft). What happens when we do this? We find our sensitivity per watt jumps from 93 dB to 96 dB. Of course, since our 8 ohm somposite spekaer is an 8 ohmer, it will get only hald the power delivered to it that the 4 ohm single speaker will, so the SPL [per 2.83 Volts will equal the 4 ohm speaker. Even though it is only drawing half the power. Because the the 8 ohm composite speaker is 3 db more sensitive per watt.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#9 |
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diyAudio Member
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One interesting thing I never realized until now. When we combine the two speakers together, and therefore double Re, Sd (Cone Area), and Vas, the the calculated BL rating also doubles from 7.99 to 15.99.
Makes sense. When we combine two speakers, we are also combining two voice coil and magnet systems as well.
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"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#10 |
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diyAudio Member
Join Date: Oct 2004
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Hmm, so does the parallel = +6dB still stand?
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