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#1 |
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diyAudio Member
Join Date: Mar 2003
Location: British Antarctic Territory
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What is the theoretical radiation pattern of a point source on an infinite plane/baffle?
Is it simply one-half of spherical, or is it more like one-half of a dipole? |
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#2 |
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diyAudio Member
Join Date: Jan 2006
Location: Aylesford, Kent, England
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It should be hemi-spherical.
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#3 | |
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diyAudio Member
Join Date: Mar 2003
Location: British Antarctic Territory
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Quote:
Consider the unit circle, x^2 + y^2 = 1. If you restrict to upper half, can be represented as a function, y = sqrt (1 - x^2) for x between -1 and 1. Now double the function, y = 2 x sqrt (1-x^2). Is no longer a semicircle, it is higher in the middle. I don't know enough about sound and stuff to tell if this is a reasonable way of looking at it. |
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#4 |
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diyAudio Member
Join Date: Aug 2004
Location: US
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(JPK) If it's a true point source then it is a hemisphere as gfinlayson stated.
__________________
John k.... Music and Design NaO Dipole Loudspeakers. |
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#5 |
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diyAudio Moderator
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Work backward and you'll see that you've changed the equation into an ellipse. "Doubling" the equation must happen on both sides to be valid.
__________________
“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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#6 |
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diyAudio Member
Join Date: Jan 2006
Location: Aylesford, Kent, England
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SY is right, you haven't doubled the function. If y = sqrt (1 - x^2), then y cannot also be equal to 2 x sqrt (1-x^2). 2 y can, however, so you still end up with a hemisphere.
Anyway, if you forget the mathematics and use common sense, a true point source radiates in a spherical pattern. So if you stick it onto an infinite plane it can only radiate in a hemi-spherical pattern. |
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#7 |
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diyAudio Member
Join Date: Mar 2003
Location: British Antarctic Territory
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I have convinced myself that it is still spherical, but not for any of the reasons you have stated.
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#8 |
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diyAudio Member
Join Date: Mar 2003
Location: British Antarctic Territory
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My mistake was taken a representation in polar coordinates and wrongly thinking of it in terms of rectangular coordinates.
Thanks for the help. |
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