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#1 |
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diyAudio Member
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I need a 12/db oct xover at 1900hz. Well this is simple enough
but I may be driving it from an amplifier with a 12 ohm output impedience. Would this high output impedience change the calculations. Thanks |
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
put simply YES, it will alter the crossover. Is that 12ohm, the output impedance or the required load impedance for that output stage? 12ohm output impedance is extremely high for a power amplifier, even for a valve amplifier with a transformer coupled output. Many a preamp has an output impedance down around that 12ohm level. These are specifically designed for driving long cables/high capacitance into the higher impedance load of the next amplifying stage. To answer the question; we cannot tell because you have not specified the two load impedances on the other side of the crossover.
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regards Andrew T. |
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#3 |
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diyAudio Member
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Andrew, thanks for the reply. I was thinking about a small
OTL amp built without feedback which explains the high output impedience. The drivers I intend to use will be 8 ohms after the zobel circuite is added. On the other hand if I use my SOZ the output impedience will be 4 ohms. Won`t this call for yet different component values ? |
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#4 |
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diyAudio Member
Join Date: Nov 2003
Location: Brighton UK
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Hi,
you've got more problems than the c/o. Amplifier source impedances of 4R and 12R will totally change the bass alignment of the speaker they are connected to. |
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| Thread | Thread Starter | Forum | Replies | Last Post |
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