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#1 |
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diyAudio Member
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Hello everybody!
Let's assume that we have single-port bass-reflex enclosure with known Vas, Fb, Sport, Lport (therefore we can calculate port quality Qp). Then we substitute initial port with N equal smaller ports with the same length Lp and with Sport/N area (each). Fb of such an enclosure will stay the same, of course (let's not consider edge effects now). The question is: What will be "new" Q'p? N*Qp? (N^2)*Qp? Something more complex? Thanks in advance! |
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#2 |
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Did it Himself
diyAudio Member
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I would imagine that the new Qp would be very slightly higher than original, and the 'scale factor' depends on how many smaller ports you use.
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www.readresearch.co.uk my website for UK diy audio people - designs, PCBs, kits and more |
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#3 |
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diyAudio Member
Join Date: Jun 2002
Location: USA, MN
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Port Q depends on more than just area, it is also drive level dependant.
Best Port Q should be with a single port vs multiple ports of the same area/length because a single port has the smallest surface/ volume ratio. What is the goal of this exercise, the point to the question?
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Our species needs, and deserves, a citizenry with minds wide awake and a basic understanding of how the world works. --Carl Sagan Science is a way of thinking much more than it is a body of knowledge. --Carl Sagan |
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#4 | |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
knowing that a small tube has more resistance to air flow than a big tube then extrapolating to a number of small tubes of equal area to a big tube. I would expect that the air resistance for equal area would be higher for a group of small tubes. This would imply that Qp would be lower. This fits Ron's comment;- Quote:
Sorry, keep asking.
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regards Andrew T. |
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