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#1 |
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diyAudio Member
Join Date: Jun 2005
Location: Adelaide
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Hi.
I'm embarking on a speaker project that specifies 46mm ID ports, and I have to admit, I'm having trouble finding any. I'm in Australia, and I'll be down the hardware and plumbing supplies soon with my calipers, but I haven't been able to find anything matching online yet. Any ideas? Thanks, Michael
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#2 |
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diyAudio Member
Join Date: Sep 2004
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I'd just go with some standard 51mm I.D. ABS and use some calc to se how many mm you need to add to the length (if you have room).
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#3 |
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diyAudio Member
Join Date: Jul 2003
Location: Newcastle, Australia
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Just recalculate the port diameter and length to suit what you can get. If you put the existing numbers in WinISD, play with the Vb, port dia, port length, you can then find the Fb (box tuning frequency).
Just change the port dia to what you can get, and the new length will appear. Use something like WinISD or what ever you have. |
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#4 |
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diyAudio Member
Join Date: Jun 2003
Location: Chamblee, Ga.
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Greets!
Or just make some square or rectangular ones with the same cross sectional area out of scrap wood. GM
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#5 | |
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diyAudio Member
Join Date: Jan 2003
Location: Mumbai, India
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Quote:
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#6 |
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diyAudio Member
Join Date: Apr 2005
Location: aus
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Jaycar sell 50mm adjustable ports.
This is pretty close to what you're after so might be worth checking out. Otherwise head down to bunnings/mitre 10 or your favourite hardware store and check out there plumbing section. |
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#7 |
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diyAudio Member
Join Date: Jul 2003
Location: Newcastle, Australia
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WES Components do sell a 45mm x 128 port (Code PT760) which would be close enough.
It's flared one end and fits in a 68mm hole. |
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#8 | |
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diyAudio Member
Join Date: Dec 2003
Location: Silicon Forest
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Quote:
Actually what is supposed to be 2 inch PVC pipes in India are perfectly 46 mm in diameter.. That's what i have used in my active speakers. |
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#9 |
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diyAudio Member
Join Date: Jan 2004
Location: Indiana
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L2 = L1*(D2^2/D1^2)+(D2-D1)^2
I was in the same situation (but going from metric to english units) and got this formula from someone here. L1 and D1 = the original length and diameter insert the new diameter D2 and solve for the new length. Its worked for me Tim |
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