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diyAudio Member
Join Date: Feb 2003
Location: Jakarta
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Suppose that we have a third order crossover for a woofer consisting of
L1=0,68mH C=11,4uF L2=0,4mH. If we place the smaller inductor (L2=0,4mH) at the input (in place of the standard position for L1=0,68mH), what do you see in phase transfer graph or SPL graph or even the waterfall? What change does it make compared to the standard? Less steeper roll-off may be? |
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