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Multi-Way Conventional loudspeakers with crossovers

impedence with self made crossover
impedence with self made crossover
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Old 18th September 2002, 10:01 PM   #1
trespasser_guy is offline trespasser_guy  United States
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Default impedence with self made crossover

If I used multiple drivers, like in a 3-way design, using a woofer and two phenolic compression drivers for mid/tweet, and hooked them to a crossover that I made, what impedence would I have if each driver is 8-ohms? I know if you average it out, like if they were all linked directly, you would have about 2 2/3 ohms... does hooking them up to any crossover make that impedence 8-ohm always? How is it determined? What must I add to make it 8-ohm? What about 4-ohm?
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Old 18th September 2002, 11:09 PM   #2
cyclotronguy is offline cyclotronguy  United States
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Impedance is a frequency related issue, you are best served by running a program like SPICE and generating a curve of frequency vs impedance.

The short answer is "there is no short answer!"

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Old 19th September 2002, 12:39 AM   #3
jackinnj is offline jackinnj  United States
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impedence with self made crossover
The crossover will present a low impedance for the passband for which it is designed, and a high impedance for the out-of-passband frequencies. It does the summing by itself.

Not to be a smart-aleck, but pick up a copy of the ARRL Handbook in virtually any library in the US and they go through the physics of why this works in terms which we can all understand.
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