Aren't 4th order LR crossovers supposed to pass squarewaves?

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Hi,

Here's my problem: I'm working on an active crossover project, and have just tested the LR4 alignment.
I thought that LR4 were supposed to pass squarewaves correctly (the summed output should be a squarewave), but mine doesn't :(

What's wrong?

Here's the (simplified) topology.
I think it's a LR4 alignment, since Q of one stage is 1/(3-Gain) and gain=1.58. Q=0.707 (butterworth)
2 cascaded 2nd order butterworth form a LR4

http://www.diyaudio.com/forums/attachment.php?s=&postid=518858&stamp=1101235143


input signal (red), the low pass output (green) and high pass output (blue)
http://www.diyaudio.com/forums/attachment.php?s=&postid=518852&stamp=1101234956



And here's the summed output

http://www.diyaudio.com/forums/attachment.php?s=&postid=518862&stamp=1101235302


Thanks for help
 
yes, it looks a little like a squarewave
 

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Bill Fitzpatrick said:
I'm almost 100% sure that when I was prototyping fourth order filters many years ago I was getting a square wave out of the summer.

I think the reason you are not is because the input square wave (1KHz) is too close to the crossover frequency(1.6KHz). Try 100Hz.

Well isn´t the point to get a decent time behaviour around the Fc..?

Well above or below a low or highpass the roll off has less and less influence.

/Peter
 
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I think some further reading is required here.

Here's a link to some information from the man that invented the Linkwitz-Riley 4th-order crossover:

http://www.linkwitzlab.com/frontiers.htm#F

The phase distortion from a 4th-order LR crossover is real. The group delay is not constant and these will not pass a square-wave undistorted. This is inherent in their design.
The big question is.....is this phase distortion audible? :)

Cheers,

Davey.
 
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