Huge box for 10" - HELP

[hazardu]

I have a Boschmann V-10df loudspeaker, 10",4ohms.The parameters are:

Fs = 35.4954
Zmax at Fs = 17.8432
Sd=0.039
Bl=8.4123
N0 (ref. eff.)=0.26
Qms=3.0122
Qes=0.8151
Qts=0.6415
Vas=48.2047
Cms (compliance?)=295.3870
Mms (total mass)=68.0621
Mmd(diafragm mass)=64.4732
Xmax=4

The results with 3 programs, showed me that i must use a box of approx. 225l liters.Isn't that too much for a loudspeaker with it's size????I have approx the same result for sealed or vented box.

[hazardu]

i forgot to say that for this box the Qtc will be about 0.7

[hazardu]

i forgot to say that for this box the Qtc will be about 0.7

[Ouroboros]

The driver Qt is 0.64, so you will need a big sealed box to have a total box Q of 0.7. Perhaps allowing a higher system Q might be OK?

This is assuming a sealed box, as a unit with a Qt this high isn't ideal for a reflex enclosure.

[djQUAN]

I'm thinking the sub is designed for infinite baffle aplications.

[hazardu]

For a 0.8 Qtc i need a 3.006 f^3 (86liters).What will be the difference?Is there a significant difference?As i understood, a lower Qtc will give a louder bass.Is that right?

[djQUAN]

and from what I remember, Qtc lower than 7 means lower deep bass extension, your sub goes lower (that's using a box bigger than the one with Qtc 0.7) and also less power handling.

with a Qtc of greater than 7, there is a bump in the bass response which adds a little more bass but not deep bass. and power handling is increased (smaller box).

[Ouroboros]

Here is a comparison of your driver in a 50L box (Q=0.9 showing a resonant peak), and in a 200L box (Q=0.715 showing a smooth roll-off).