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#1 |
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diyAudio Member
Join Date: Jul 2003
Location: Silicon Valley
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There's a worksheet on Martin's site for an fe206e: http://www.quarter-wave.com/Project05/FE_206E_ML_TL.pdf
It contains the following formula, which appears to be intended for changing Qed (a.k.a. "Qes") based on added resistance. Qed := 0.18*Re*(Re-Radd)^-1 (I attached the actual text below to show I didn't miscopy it.) The Amazing Martin tosses partial differential equations around like tennis balls, but is that right? When Radd is 5 ohms, Qed works out to 0.737. I believe it should be 0.263.
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Davy Jones |
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#2 | |
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Account disabled at member's request
Join Date: Feb 2002
Location: Clifton Park, NY
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Dave,
Quote:
Back to the worksheet in question. I think that you need to look at the worksheet again, please don't focus on just one equation since it is really a series of steps. For the FE-206E the manufacturer's specs state the following values : Re = 6.69 ohms Qed = 0.18 (really Qes for the rest of the world) In the worksheet, I define the following relationships. Radd = 3 ohms then Re = 6.69 + Radd = 9.96 ohms Qed = 0.18 x 9.69 / 6.69 = 0.26 I set things up this way so that I only have to change Radd and everything flows from there. Hope that helps, |
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#3 | |
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diyAudio Member
Join Date: Jul 2003
Location: Silicon Valley
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Quote:
Thanks for the help.
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Davy Jones |
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