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MultiWay Conventional loudspeakers with crossovers 

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3rd June 2004, 04:12 PM  #11 
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Graph:
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Davy Jones 
3rd June 2004, 04:13 PM  #12 
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Code:
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Davy Jones 
3rd June 2004, 04:32 PM  #13 
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Here, this is a better picture. I cut the graph off at 20 Hz rather than 10.
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Davy Jones 
3rd June 2004, 05:02 PM  #14 
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Oops, I didn't look at the box equations too closely.
To modify, you can take the square root of the box response equation So: P(f)= Fn4/sqrt((Fn4C*Fn2+A)^2+Fn2*(D*Fn2B)^2) A(f) = ff2/sqrt((1ff2)^2+(ff2/Q^2)) B(f) = 1/sqrt((1fc2)^2+(fc2/Q^2)) The response of the woofer + HP filter + LP crossover is then 20*log10(A(f)*B(f)*P(f)) You will want to try to graph with semilog scales to get decent looking output. You notice that you get 5dB at 30 Hz rather than at the peak, that is because the formula I gave you is for dB at te hfilter frequency, not at the peak. Looks Good!
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3rd June 2004, 06:27 PM  #15  
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Quote:
I'm confused again. What is F_crossover? That's a new one. And there's a whole new part to the formula. Sorry if I'm being dense. Are you showing how to model both the bass boost and the infrasonic filter that plate amps usually have? And if so, is F_crossover the frequency of the knee of the infrasonic (high pass) filter? Or what?
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3rd June 2004, 07:39 PM  #16  
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Quote:
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4th June 2004, 07:07 PM  #17 
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I got it. Thanks again. Here's the chart on a log scale:
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Davy Jones 
4th June 2004, 07:28 PM  #18  
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The boost graph appears to be right. I don't think I've got the crossover right though.
Questions please: Quote:
2) I presume "f" is "F", right? I think when I get this figured out, I'm armed for bear.
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4th June 2004, 08:11 PM  #19 
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Hmmmm.... If I use Q = 1/sqrt(2) in the crossover equation, I get what looks like it might be the right curve.
Below is the combined boost and crossover. What's that Q supposed to be?
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Davy Jones 
4th June 2004, 08:17 PM  #20 
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Combined:
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