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#1 |
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diyAudio Member
Join Date: Feb 2003
Location: New Zealand
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Some suggest using lower quality/priced components in the non-signal critical areas of crossovers such as paralleled components that are effectively only shunting to ground.
But does the DCR of coils matter here as much as it does in the signal path? Mos |
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#2 |
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diyAudio Moderator Emeritus
Join Date: Jan 2002
Location: Michigan
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So the question is whether the distortion created by a parallel component that shunts to ground can affect the signal to the output, in this case a speaker.
If you assume the distortion is in fact generated in a “lower quality” component, that distortion will be manifest in a voltage other than ideal (different from the signal). Since the component is shunting from the signal path to ground, it has at least one node (connection) in the signal path. The distortion generated by the component has to exist at this signal path node. So the answer has to be yes, this component, even though it is not in the signal path, will affect the actual signal. So the real question should be will the “high quality” component generate less distortion than the lesser quality component, in the signal path or not?
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Rodd Yamashita |
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#3 |
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diyAudio Member
Join Date: Feb 2003
Location: New Zealand
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What I'm asking is not related to distortion, it's related to the resistive action of a parallel component. Unless you count resistance as distortion, that is.
So, explicitly: does a higher resistance coil in parallel with the signal path impart any more resistance to the signal path than a lower resistance coil would? Mos |
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#4 | |
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diyAudio Moderator Emeritus
Join Date: Jan 2002
Location: Michigan
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Quote:
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Rodd Yamashita |
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#5 |
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diyAudio Member
Join Date: Jul 2003
Location: Newcastle, Australia
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Hi Mos
I read somewhere that the DCR of the inductor should be less than 10% of the voice coil DCR. So for a driver with a DCR of 5.7ohm the inductor should have a DCR less than 0.57ohm. Apparently so it has little affect on the driver Q. Thiele states that 5% will not affect driver Q. Hope this helps. |
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