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#1 |
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diyAudio Member
Join Date: Feb 2003
Location: North London
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Hi Guys. I'm interested in your views here on a subject that may be quite relevant to those designing tall, thin floor-standing speakers.
Say we take a sealed box design and stretch it while keeping the volume constant so that it becomes taller and less deep and wide. When does it start to act like a closed transmission line? |
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#2 | |
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Banned
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Quote:
*scratches head* closed transmission line? |
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#3 |
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diyAudio Member
Join Date: Jul 2003
Location: Seattle, WA
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Do you lie awake at night thinking of questions like this? I don't know. Are we talking about setting up a 1/4 wave inside the enclosure? What happens with the pressure changes?
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#4 |
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Account disabled at member's request
Join Date: Feb 2002
Location: Clifton Park, NY
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Hi Steve,
I assume you are talking about a closed ended transmission line which exhibits half wavelength standing waves. If that is the case, then I think the answer to your question is that all closed boxes are transmission lines. The real question is at what frequency the transistion from a lumped parameter closed box model to a standing wave closed box model occurs. This is determined by the longest dimension of your closed box. f = c / (2 x L) So as length increases, the frequency at which the first standing wave occurs decreases. You can calculate this frequency for all three dimensions of a rectangular closed box. The next problem is how much do the standing waves impact the driver SPL response. This will be determined by the position of the driver along the length and it may be that it is not until you excite the higher order standing waves that problems occur. Also, closed boxes are typically stuffed so any standing waves will be damped. My MathCad worksheet "Closed Box" does this type of simulation for one dimension. Hope that helps, |
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#5 |
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diyAudio Member
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Martin:
In your equation: f = c / (2 x L) Does "c" stand for the speed of sound per second, which is 13,500 inches?
__________________
"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#6 | ||
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diyAudio Member
Join Date: Feb 2003
Location: North London
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Quote:
Quote:
BTW, is anyone going to be at the Bristol Show next month? I'll be exhibiting there. |
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#7 | |
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Account disabled at member's request
Join Date: Feb 2002
Location: Clifton Park, NY
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Hi keltic wizard,
Quote:
f = (2 x pi x c) / (2 x L) When I use MathCad it keeps the units straight for me so I tend to not pay attention. If you are using a calculator the formula above results in the correct units of Hz. |
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#8 |
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diyAudio Member
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Martin:
Thank you. Just one more question. In the equation: f = (2 x pi x c) / (2 x L) Does pi stand for pi, (3.14), or some other number?
__________________
"A friend will help you move. A really good friend will help you move a body." -Anonymous |
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#9 | |
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Account disabled at member's request
Join Date: Feb 2002
Location: Clifton Park, NY
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kelticwizard,
Quote:
ph = 3.14159265........ Maybe I should give it a rest and take a nap. Audrey is taking the kids out to the mall, I know I probably have something I am supposed to be doing .... but a nap sounds good. |
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#10 | |
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diyAudio Member
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Quote:
__________________
What the hell are you screamin' for? Every five minutes there's a bomb or somethin'! I'm leavin! bzzzz! Droggon Attack! |
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