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Multi-Way Conventional loudspeakers with crossovers

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Old 25th November 2003, 05:41 PM   #1
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Default Total Impendance?

Hi, i was wondering how you work out the total impedance of a loudspeaker if it uses the MTM configuration? surely in this case you would have an 8 ohm tweeter and the 2 woofers (presumably 8 ohms each) in parallel to give you 4 ohms, what i don't understand is what does the amp see if this is the case? Wouldn't there be a problem if the impendance is swaying between 4 and 8 ohms depending on which frequencies are playing. I think i'm missing something here so could someone please fill me in.
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Old 25th November 2003, 07:01 PM   #2
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In my case the woofers were under 8 ohms, ~5 1/2. You also need to account for impedance introduced by the crossover. This is where much of your impedance matching can take place.
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Old 25th November 2003, 09:37 PM   #3
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I had to read this again. If you wire two 8 ohm drivers in parallel giving 4 ohm, then in parallel again to an 8 ohm tweeter you get around 6 ohm, then factor in the resistance of your crossover you'll come in somewhere between 6 and 8 I would think. Whichever you come up with most amplifiers will not have a problem driving speakers in the 4 to 8 ohm range. As for swinging, the actual resistance that exists will range quite a bit farther than just a 4 ohm swing anyway.
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Old 26th November 2003, 01:23 AM   #4
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ok thanks, i think i understand now. Just wasn't sure whether there was a drop in impedance when lower frequencies were being played and if so would the amp handle them. But if i follow most of the MTM designs i should be ok i think, because many i've seen include crossovers.
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Old 26th November 2003, 01:58 AM   #5
Ilianh is offline Ilianh  Canada
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Depending on your crossover, Imagine Coils and Caps as frequency dependant resistors,

you can calculate that resistance as Xc = 1/(2PIfc) And Xl=2PIfl

Xc is at -90 degrees, Xl is at 90 degrees.

for eg. If you have a 4 uF cap and a 8 ohm tweeter in series, at 2000 hz, Xc = -19.8i <- That shows its at 3/4 PI.

Now you have you tweeter thats in series,

So Zt = 8 + -19.8i = sqrt (8^2 + 19.8^2)= 21.3 Ohms (with an angle, of course)

For those interested, the angle of the impedance is tan^-1 of 8/19.8 = 22.03 degrees, so 45 degrees - 22.03 degrees =
22.97 degrees

as here we are in the fourth quadrant, thats -22.97 degrees or 337 degrees..

For paralell components, (R1^-1+R2^-1+Rn^-1)^-1

So here, open Excel... and make something nice....
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