Baffle step compensation in an active X/O

Status
This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.
Hi,

I hope this is the right forum to post this question.
I'm making an active X/O based on John Pomann's design.

http://www.snippets.org/filters/crossover.htm

I need to calculate the C's & R's for a baffle step
compensation circuit.

I'm using Alex Megann's writeup on:

www.t-linespeakers.org/tech/bafflestep/bstepcompo.html

Now from what I understand, the geometric mean for the midpoint
of the step is calculated by the square root of 2 which gives the 3db point, 2 being 6db. How do I calculate the rest ?
Eventually I want to be able to switch from 0 to 1, 1.5, 2, 2.5
& 3db points.

Also, I would like some help from people who are using Active X/O's to know whether it would be worth the effort & if, then should I build the X/O past the 3db point.

Any other ramblings would be welcome.

Cheers,
sunil
 
Status
This old topic is closed. If you want to reopen this topic, contact a moderator using the "Report Post" button.