Baffle step compensation in an active X/O - diyAudio
 Baffle step compensation in an active X/O
 User Name Stay logged in? Password
 Home Forums Rules Articles diyAudio Store Gallery Wiki Blogs Register Donations FAQ Calendar Search Today's Posts Mark Forums Read Search

 Multi-Way Conventional loudspeakers with crossovers

 Please consider donating to help us continue to serve you. Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving
 26th October 2003, 08:47 AM #1 diyAudio Member   Join Date: May 2003 Location: Bangalore, INDIA Baffle step compensation in an active X/O Hi, I hope this is the right forum to post this question. I'm making an active X/O based on John Pomann's design. http://www.snippets.org/filters/crossover.htm I need to calculate the C's & R's for a baffle step compensation circuit. I'm using Alex Megann's writeup on: http://www.t-linespeakers.org/tech/b...stepcompo.html Now from what I understand, the geometric mean for the midpoint of the step is calculated by the square root of 2 which gives the 3db point, 2 being 6db. How do I calculate the rest ? Eventually I want to be able to switch from 0 to 1, 1.5, 2, 2.5 & 3db points. Also, I would like some help from people who are using Active X/O's to know whether it would be worth the effort & if, then should I build the X/O past the 3db point. Any other ramblings would be welcome. Cheers, sunil

 Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is OffTrackbacks are Off Pingbacks are Off Refbacks are Off Forum Rules

 Similar Threads Thread Thread Starter Forum Replies Last Post Mikett Multi-Way 21 8th June 2014 10:40 AM tmblack Multi-Way 28 6th December 2008 12:39 PM wigginjs Multi-Way 17 31st January 2008 06:44 PM Khron Multi-Way 4 16th April 2006 08:23 PM sunil Solid State 6 12th November 2003 09:52 AM

 New To Site? Need Help?

All times are GMT. The time now is 03:53 AM.