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#1 |
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diyAudio Member
Join Date: Dec 2007
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I have a 6" two way tower speaker that I may add a larger woofer to for more extended bass.
I read somewhere that there is a floor-bounce cancellation related to woofer height (Allison effect?). The 6" driver is approximately 30 inches from the floor. How do I determine the frequency at which this occurs, and how will/should this affect my choice of lower-end crossover frequencies? Thank you. Joe |
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#2 |
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diyAudio Member
Join Date: May 2008
Location: Mountain View, CA
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#3 |
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diyAudio Member
Join Date: Mar 2007
Location: California
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This Excel spreadsheet based modeler written by Jeff Bagby does the same, and more:
Loudspeaker Design Software -Charlie |
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#4 |
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diyAudio Member
Join Date: Nov 2010
Location: North Lanarkshire, UK
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For a really quick, back of the napkin calculation, there is also this useful page:
Floor/Ceiling Reflection Calculator
__________________
- Simon |
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#5 | |
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diyAudio Member
Join Date: Jul 2006
Location: Calais, ME
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Quote:
The cancellation doesn't show up in near field measurements. However, when the mic was placed 1 meter away, an in-room 20-20K ungated sweep registered a deep notch at approx 150Hz. That's one reason why mid-bass is missing sometimes. More measurements can be found at SWIFT
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AmpsLab.com |
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#6 | |
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diyAudio Member
Join Date: Mar 2007
Location: California
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Quote:
-Charlie |
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#7 | |
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diyAudio Member
Join Date: Feb 2004
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Quote:
I tend to suggest flanking subs to mitigate this problem. Run a "helper woofer" just a smidge on the high side, like just north of 100Hz. It will smooth the lower midrange, sort of filling in the holes from the self-interference notches. |
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#8 |
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diyAudio Member
Join Date: Feb 2004
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Definitely. I either run a three-way with mid and woofer blended between 100Hz and 250Hz or, if I run a stand-mounted two-way, I run flanking subs, which effectively do the same thing. I don't usually run flanking subs quite that high, but I do let them blend in the octave above 100Hz.
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#9 |
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diyAudio Member
Join Date: May 2007
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It's dead simple both to visualize and to calculate. You have to imagine a mirror image of the driver deep inside the floor. When sound emission from the driver itself and from this subterranean image are in antiphase, there is cancellation. This happens when path length difference is half a wavelength. You calculate the path length difference by calculating two hypotenuses and subtracting one from the other, and then divide the speed of sound by the result: this number is twice the frequency in question.
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