|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
| Multi-Way Conventional loudspeakers with crossovers |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
|
![]() |
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
Join Date: Mar 2011
|
Hello,
I will build an loudspeaker with Monacor SPH-170 (18.5 centimeters outer diameter) woofer and Monacor DT-25N tweeter (6.6 centimeters outher diameter). What is the formula for calculating the maximum distance between the centers of the drivers? The active crossover frequency is 3410 Hz / 24dB Linkwitz-Riley. I've searched over the web and found this formulas : 1. max distance = wavelength of crossover frequency / 3.14 / crossover frequency 2 max distance = wavelength of crossover frequency / 2 but i guess both are wrong, because the length of the wave is : 150000.00 meters for 2000 Hz 88235.29 meters for 3400 Hz 11.11 meters for 27Mghz 2.08 meters for 144Mghz Does any one know the right formula? |
|
|
|
|
#2 |
|
diyAudio Member
Join Date: Apr 2007
|
Hi ,try to keep them as close as possible ,to simulate a 'point source' .
I've got a Secret Formula It's sound in air velocity (344 m/s ... ) / the frequency. The Seconds misteriously disappear in that equation ,and you have only the Length !!! |
|
|
|
|
#3 |
|
diyAudio Member
Join Date: Oct 2008
|
@ pico, what chance do people like me have when you keep withholding the formulas
@kategra, it's light that travels at 300Mm/s |
|
|
|
|
#4 | |
|
diyAudio Member
Join Date: Oct 2008
Location: Winterswijk
|
Quote:
place them is close as possible to reduce lobes. Within wave length signal is coupled and will gain each other.
__________________
( (( KUGELWELLE )) ) recent projects :OB-mk1 /fatboy / monitor-xl / Horn-AM / dappolito / td124-mk1-rb301 / Hybrid-pse / Vfet |
|
|
|
|
|
#5 | |
|
diyAudio Member
|
Quote:
b |
|
|
|
|
|
#6 |
|
diyAudio Member
Join Date: Mar 2011
|
Thank you. I built the loudspeakers, 14.3 cm distance from center to center; i also changed the XO frequency to 2600 Hz.
I implemented a Baffle Step Compensation filter in my active XO, but i think i got it wrong, i no longer find the web page (searched in browser history, the web all day and night ) with the examples different ways to implement the BSC using different opamps circuitry (inverting, noninverting, etc). That web page also provided the formulas to calculate the component values, gain, corner frequencies. I accidentally threw away the paper on which i copied the inverting circuit and made the calculations. I used R1=680 ohms, R2=1 Kohm, R3=4.3 Kohms , C1=220nF From what i remember it should have an 3-4 dB gain at ~100 Hz with a gain of 0 db at ~450 hz. But now i am not sure any more, i think the speakers are sounding a little to thin, music sound good if boost the bass 2-3 db in my Audigy2 eq panel. Does anyone have the formulas for this schematic? Last edited by kategra84; 28th May 2011 at 08:34 AM. |
|
|
|
|
#7 |
|
diyAudio Member
Join Date: Mar 2011
|
I changed R2=2.5 k and R3=820 ohms and now it sounds great!
Last edited by kategra84; 28th May 2011 at 05:00 PM. |
|
|
![]() |
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
| New To Site? | Need Help? |
| Page generated in 0.08889 seconds (76.52% PHP - 23.48% MySQL) with 10 queries |