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Multi-Way Conventional loudspeakers with crossovers

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Old 14th March 2011, 11:19 AM   #1
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Default baffle diffraction correction and crossover network.

I am designing satellite speakers. this has one tweeter, mid woofer.
I mid woofer is 4 Ohms. so I designed crossover to suit 4Ohms driver. Now the upper cut off is at 3.5KHz and lower is 100Hz. Baffle diffraction correction is at 1 KHz. now my problem is, if I connect correction circuit between driver and crossover filter. Then the impedance of driver seen by crossover is frequency dependent. So this might lead to improper functioning of crossover filter.

Am I right? What Do I do ?
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Old 14th March 2011, 02:44 PM   #2
rho is offline rho  Belgium
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A loudspeaker x-over network is always frequency dependent. A loudspeaker is not a resistive load.
Besides that you have to take into account that there is no speaker with a perfect frequency response. So a theoretical calculation, based on a 4 ohm resistive load will yield results far from reality.
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Old 14th March 2011, 06:31 PM   #3
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Originally Posted by rho View Post
A loudspeaker x-over network is always frequency dependent. A loudspeaker is not a resistive load.
I agree, and So we use impedance matching ckt.

But still its with Baffle correction, in my case, filter network will see 8 Ohms for higher frequency and 4 Ohms below correction frequency ( it will be gradual change from 4 Ohms to 8 Ohms).
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Old 17th March 2011, 02:33 AM   #4
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Just one reply? no one ?
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Old 17th March 2011, 01:03 PM   #5
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Originally Posted by Aucosticraft View Post
Just one reply? no one ?
Probably because most posters here are into single driver speakers and the word "crossover" is only spoken softly.

Bob
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Old 17th March 2011, 01:04 PM   #6
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Assuming I understand what you're doing....

Let's say you have a plexiglass tube, 3" x 12". You want to fill it 1/2 full of yellow water and 1/6 full of red water. Your questions equates to saying, "After I pour in the yellow water and start pouring in the red water, it mixes and makes orange, so I can't see how much red water I've added."

You can't "stack" passive filter sections. The inductor in your crossover will combine with the inductor in your baffle correction circuit and you'll get one roll-off, not two.
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Old 18th March 2011, 07:03 PM   #7
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@ Mr. Keriwena ,Have a look at the diagram attached, and try to understand the difference. ignore the value of components.
Attached Images
File Type: png Difference.png (4.5 KB, 136 views)
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Old 19th March 2011, 04:34 AM   #8
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Ah, yes, now I understand. You don't have a Zobel.

Maybe this 3rd order low pass looks familiar:
Click the image to open in full size.


I'd follow Rod's advice, myself:
Baffle Step Compensation


And that's Miss Keriwena to you.
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Old 21st March 2011, 01:49 PM   #9
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Well Miss Keriwena, (hope I am correct this time. ).

I am using zobal network but just did not put here. just for better understanding.
Compare the circuit again its not same..
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Old 21st March 2011, 02:21 PM   #10
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Rod has put a lot good words on Baffle Step Compensation (BSC). Rather I say he has put lot of explanation on Audio. His site is one of my favorite bookmark.

I am looking for a deeper explanation. A simple question for you, which two sides would you use? so would say other two sides ( of four sides) has no effect on BSC ?

I got some link more on BSC. read it too.

I use Edge for deeper calculations.
Still the actual curves are nearly same. I wont say you strictly need Edge. but its better.
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